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3 years ago

What is the value of s in the equation below s+2 1/12=61

Mathematics

1 answer:

choli [55]3 years ago

5 0

STEPS FOR SOLVING LINEAR EQUATION

s+2 2/1 =61

Multiply both sides of the equation by 2.

2s+2×2+1=122

Multiply 2 and 2 to get 4.

2s+4+1=122

Add 4 and 1 to get 5.

2s+5=122

Subtract 5 from both sides.

2s=122−5

Subtract 5 from 122 to get 117.

2s=117

Divide both sides by 2.

s= 2117... i think :)

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283 rounds to nearest tens place

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The answer is quite simple the question is more so as 6·y = 144
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Pachacha [2.7K]

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Answer:

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Step-by-step explanation:

In the right triangle, the hypotenuse is 25 feet long. The area of this triangle is 84 square feet.

Let x feet and y feet be the lengths of triangle's legs.

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$\left\{\begin{array}{l}x^2+y^2=625\\ \\xy=168\end{array}\right.$

From the second equation:

$x=\dfrac{168}{y}$

Substitute it into the first equation:

$\left(\dfrac{168}{y}\right)^2+y^2=625\\ \\168^2+y^4=625y^2\\ \\y^4-625y^2+168^2=0\\ \\D=(-625)^2-4\cdot 168^2=(625-2\cdot 168)(625+2\cdot 168)=289\cdot 961=17^2\cdot 31\\ \\\sqrt{D}=17\cdot 31=527\\ \\y^2_{1,2}=\dfrac{-(-625)\pm 527}{2}=49,\ 576\\ \\y_1=7,\ y_2=-7,\ y_3=24,\ y_4=-24$

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