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BartSMP [9]
3 years ago
9

What is the remainder of x^4-6x^3-10x^2+20x+15

Mathematics
1 answer:
sergejj [24]3 years ago
8 0

Answer:

0 - 1

Step-by-step explanation:

U can do by simple division method to get the answer

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A number is 3 1/3 greater than another. If the sum of the numbers are doubled the answer would be 19 1/2
Delicious77 [7]

Answer:

smaller number = 3 5/24

larger number =  6 13/24

Step-by-step explanation:

let the larger number = x

smaller number = y

x - y = 3 1/3 equation 1

2(x +y) = 191/2 equation 2

divide equation 2 through by 2

x + y = 9 3/4  equation 3

subtract equation 1 from 3

2y = 6 5/12

y = 77/12 x 1/2 = 3 5/24

substitute for y in equation 1

x - 3 5/24 = 31/3

x = 3 1/3 + 3 5/24

x = 6 13/24

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2 years ago
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Harlamova29_29 [7]

Answer:

y= -1x + 2

Step-by-step explanation:

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2 years ago
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WARRIOR [948]
3 minutes and 36 seconds is the length of "Shake it off" by Taylor swift.

Source: Wikipedia
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3 years ago
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1. What is the slope-intercept form and what information does it give you?
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3 years ago
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A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{5\% alloy}&x&0.05&0.05x\\&#10;\textit{30\% alloy}&y&0.30&0.3y\\&#10;-----&-----&-------&-------\\&#10;mixture&100&0.15&15&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+y=100\implies \boxed{y}=100-x\\&#10;0.05x+0.3y=15\\&#10;----------\\&#10;0.5x+0.3\left( \boxed{100-x} \right)=15&#10;\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
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3 years ago
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