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VikaD [51]
3 years ago
9

Max sneezes every 5 minutes, Lina coughs every 6 minutes, and their dog barks every 3 minutes. If there was sneezing, barking, a

nd coughing at 3:15 PM, when is the next time that these three sounds will happen simultaneously?
Mathematics
2 answers:
BARSIC [14]3 years ago
6 0

Answer:  The next time at which the three sounds will happen simultaneously at 3 : 45 PM.

Step-by-step explanation:  Given that Max sneezes every 5 minutes, Lina coughs every 6 minutes and their dog barks every 3 minutes.

We are to find the time at which these three sounds will happen simultaneously if there was sneezing, barking, and coughing at 3:15 PM.

We have

the sneezing, barking and coughing happen simultaneously at an interval that is equal to the L.C.M. of 5, 6 and 3 minutes.

Now,

L.C.M. (5, 6, 3) = 30.

Therefore, the sneezing, barking and coughing happen simultaneously at an interval of 30 minutes.

Since there was sneezing, barking, and coughing at 3:15 PM, so the next time at which the three sounds will happen simultaneously is

3 : 15 PM + 30 min = 3 : 45 PM.

Thus, the next time at which the three sounds will happen simultaneously is 3 : 45 PM.

Phantasy [73]3 years ago
4 0

Answer:

3:45 PM

Step-by-step explanation:

The least common multiple of 3, 5, and 6 is 30, so the next occurrence will be 30 minutes after 3:15 PM, at 3:45 PM.

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Solve each equation x-6=8
jok3333 [9.3K]
Equation is
x-6=8
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x=14
X equal to 14
8 0
3 years ago
The locations:
GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

AD = \sqrt{(-2 -6)^2 + (3 -8)^2}

AD = \sqrt{89}

CD = \sqrt{(10 -6)^2 + (2 -8)^2}

CD = \sqrt{52}

AB = \sqrt{(-2 -4)^2 + (3 +6)^2}

AB = \sqrt{117}

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
2 years ago
PLZ HELP 100 POINTS A triangle has two sides with lengths 7 m and 12 m.Which of the following lengths could represent the length
Vinil7 [7]

Answer:

7, 10, 17

Step-by-step explanation:

4m can' t be the third side because the second side, 12m must be less than the sum of the first and third sides and can't be 19m because 19 must be less than the sum of the first and second sides.

As a rule, the measure of a side of a triangle must be less than the sum of the measures of the 2 other sides

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3 years ago
Need help!!! I dont get it
lesya692 [45]

Answer:

4/3π - √3

Step-by-step explanation:

Pie piece of circle is area of circle x portion of circle

πr²*x/360 = π(2)²*120/360 = 4/3π

Then you must subract the non-right triangle area

1/2ab sin C = 1/2(2)(2) sin 120 = 2 * √3/2 = √3

4/3π - √3

7 0
3 years ago
Consider the following switch statement where x is an int. If x is currently equal to 5, what will the value of x be after the s
Sphinxa [80]

Answer:

x=11

Step-by-step explanation:

The switch case works like an if or if-else, where each of the cases are conditionals. Here we have 7 cases and we know that our variable begins with x=5.

First, it enters to case 5 because of x=5, so x+=3, this means we add 3 to the actual value of the variable ⇒ x=8.  

At this point, if there's not break the program continues to the next case, executing the statements until a break or the end on the switch is reached.  

In this order, the x = 8 and next we add 1 (case 6) ⇒ x=9. We add 2 (case 7) x+=2 ⇒ x=10. Then we rest 1 (case 8) ⇒ x=9 and then we add 1 again as in case 9 ⇒ x=11.

3 0
3 years ago
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