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SVETLANKA909090 [29]
3 years ago
11

10. Explain how proving two triangles congruent can help prove parts of the triangle congruent.

Mathematics
1 answer:
forsale [732]3 years ago
5 0

Answer:

if two angles r equal or sides r proportional

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The radii of earth and Pluto are 6,371 kilometers and 1,161 kilometers, respectively. Approximately how many spheres the size of
SCORPION-xisa [38]
Earth volume: (3/4).π.(6371)³ = 1,0832x10¹² km³

Pluto volume: (3/4).π.(1171)³ = 6,555,189,765 km³

How many spheres the size of Pluto does it take to have the same volume as earth?

volume Earth/ volume Pluto = 1,0832x10¹² / 6,555,189,765 = 165.25
3 0
3 years ago
Read 2 more answers
I just cant remember how to do these ones. been so long<br><br>Solve 2x – 5 = 7​
TEA [102]

Answer:

2x=7+5

2x=12

X=12/2=6

Kskwkjxu

8 0
2 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
Find the mode of the following data:
frutty [35]

Answer:

Step-by-step explanation:

The data which has higher frequency in the given data set is the mode.

Mode = 33

5 0
2 years ago
Evaluate the piecewise function at the given values of the independent variable solver
Goryan [66]
X | x ≤ 1} and {x | x ≥ 1}{x | x < 1} and {x | x > 1}<span>{x | x ≤ 1} or {x | x ≥ 1}

.

</span>
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