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Softa [21]
3 years ago
13

Use the difference of squares identity to write this polynomial expression in factored form: 9x2 − 49.

Mathematics
2 answers:
qwelly [4]3 years ago
7 0
9x^2-49
It equals:
<span>(<span><span>3x</span>+7</span>)</span><span>(<span><span>3x</span>−7</span><span>)
Hope this helps!
</span></span>
Kisachek [45]3 years ago
5 0

Answer:

(3x+7)(3x-7)

Step-by-step explanation:

Use the difference of squares identity to write this polynomial expression in factored form:  9x^2-49

Difference of square formula is

a^2-b^2=(a+b)(a-b)

9 can be written as 3^2

49 can be written as 7^2

9x^2-49

(3x)^2-7^2

The value of 'a' is 3x  and b is 7

a^2-b^2=(a+b)(a-b)

(3x)^2-7^2=(3x+7)(3x-7)

(3x+7)(3x-7)

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tester [92]

The amount of money I would repay in the first month is $166.67.

The amount of money I would repay in the second month is $166.67.

The amount of money I would repay in the third month is $166.66.

<h3>How much would I repay each month?</h3>

In order to determine the money that would be repaid each of the first two months, multiply 1/3 by the amount of the loan.

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To learn more about loans, please check: brainly.com/question/25811386

8 0
2 years ago
Pls help me im sooo stuck on math​
Alla [95]
87

You can add up the angles that are labeled(73,110,and 90 because of the right angle) and get 273.

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Hope this helps:)
8 0
3 years ago
F(x) = 4x - 9 step by step and put the right anwser so I can read it
butalik [34]
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7 0
3 years ago
Factorise the following quadratic equations ​
vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

In 13 - 17

Consider the factors of the constant term which sum to give the coefficient of the x- term

13

x² - x - 42 = (x - 7)(x + 6)

15

x² + x - 6 = (x + 3)(x - 2)

17

x² - 27x + 50 = (x - 25)(x - 2)

19

r² - 25 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , thus

r² - 25

= r² - 5² = (r - 5)(r + 5)

5 0
3 years ago
Read 2 more answers
If f(x) =2x²-x, find f(-4)-f(9)​
sergeinik [125]
F(-4) = 36
f(9) = 153
3 0
3 years ago
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