Where is the pic of the angles to measure ? I would help
You
Since your slope is 3, (the number for slope is always right before x) and your y-intercept is one (that is always the number after the x) your answer would be B
Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
1 → B
multiply each term in the parenthesis by the 6 outside
6(b-7) = 6b - 42
2 → D
multiply each term in the parenthesis by the 3 outside
3(4x+6y+2) = 12x+18y+6
3 → A
the value outside the parenthesis is -1, hence each term inside is multiplied by -1
-1(6x+5y) = -6x -5y
