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deff fn [24]
3 years ago
14

Just member 5 and 6

Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0
5. 275 6.57 hope it help
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Answer:

1 gallon and one pint I hope this helps and I hope it's not wrong

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2 years ago
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Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1
algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
2 years ago
Julio has $40.00 to rent bikes for himself and a friend for 5 hours. Each bike
tia_tia [17]

Step-by-step explanation: if its asking  how much money he spends in total you multiply

$3.25 x 5 = 16.25

4 0
2 years ago
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HELP ME PLS?? <br> 2 divided by 1/2= ??
Gennadij [26K]
The answer is 4
Because 0.5 times 4 is 2
5 0
3 years ago
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Sam and Elise had 41 peaches left at his roadside fruit stand. Sam went to the orchard and picked more peaches to stock up the s
uysha [10]

Answer:

Sam picked 27

Step-by-step explanation:

41-8=33

33+27=60


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3 years ago
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