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user100 [1]
3 years ago
15

quien me ayuda explicando el proceso de realizar esta funcion cuadratica para encontrar el vertice y=−4x−5

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

-9

Step-by-step explanation:

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Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2
pshichka [43]
a_n_+_1=-4a_n_+_2

dividing both sides by -4, we get:

a_n_+_2=- \frac{a_n_+_1}{4}

this means, each term is its previous term divided by -4.

now we can construct the sequence as follows:

a_1=2

a_2=- \frac{a_1}{4}= - \frac{2}{4}= -\frac{1}{2}

a_3=- \frac{a_2}{4} =- \frac{ \frac{1}{2} }{4}=- \frac{1}{8}

a_4=- \frac{a_3}{4}=- \frac{ \frac{1}{8} }{4}=- \frac{1}{32}



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2 years ago
Line DCE is parallel to line AB
krek1111 [17]

Answer:

Angle DCA = Angle CAB. (Alternate Interior Angle)

Angle DCA = 68°

Angles(DCA + ACB + BCE) = 180°. (Linear Pair)

Angle ACB + 68° + 33° = 180°

Angle ACB = 79°

Therefore,

Angle ABC = 33°. (Alternate Interior Angle)

4 0
3 years ago
Write the equation of the circle centered at (3, 5) and tangent to x = -1. I need help pleasse
Annette [7]

Answer:

(x - 3)² + (y - 5)² = 16

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

given (h, k ) = (3, 5 ) we require to find r

r is the distance from the centre to a point on the circle

given x = - 1 is a tangent the r is the distance between the x- coordinates

r = | 3 - (- 1) | = | 3 + 1 | = | 4 | = 4

then equation of circle is

(x - 3)² + (y - 5)² = 4² , that is

(x - 3)² + (y - 5)² = 16

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2 years ago
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Jlenok [28]
1.3 meters below the surface of the water
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2 years ago
Read 2 more answers
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