Answer:
24 im pretty sure.
Step-by-step explanation:
Step-by-step explanation:
Hey there!
Follow the steps to get answer.
- Use one point formula and find 1st equation.
- After that you find the slope of second equation.
- Use the condition of perpendicular lines and find the slope of first equation.
- Put slope value of equation in equation (i) and simplify them to get equation.
The equation of a line passing through point (2,3) is;
(y-3)= m1(x-2).......(i).
Another equation is;

2nd equation..
Now, From equation (ii)
We have;
Comparing equation (ii) with y = mx+c.
We get;
Slope = -1/2.
For perpendicular lines,


Therefore the slope is 2.
Put value of slope (m1) in equation (i). We get;

Simplify them to get equation.


Therefore the required equation is y = 2x-1.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
You could multiply 6 times 3 to get your answer. The answer would be 18
For a width of 25, the length will also be 25, so the area is 25² = ...
625.
_____
The rule is
area = width×(50 -width)
Answer:
a. v(t)= -6.78
+ 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=
=
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒
v' + k
v = g
⇒ [v
]' = g
. Integrating, we have
∫ [v
]' = ∫g
v
= 
+ c
v(t)=
+ c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c
= 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78
. m/s = - 6.78
+ 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78
+ 16.33 m/s = 16.328 m/s ≅ 16.33 m/s