H 1 : H 2 = 4 : 10
H 1 = 2/5 H 2
and also for the base: L 1 = 2/5 L 2 and W 1 = 2/5 L 2
A 1 = 2 L 1 x W 1 + 2 L 1 x H 1 + 2 W 1 x H 1
A 2 = 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 x H 2
A 1 / A 2 = 4/25 *( 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 H 2 ) /
/ ( 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 x H 2 ) =
= 4/5
A 1 : A 2 = 4 : 25
Answer: B ) 4 : 25
We'll assume this is an arbitrary triangle ABC.
A) No, the sines of two different angles can be whatever they want
B) sin(B)=cos(90-B)
Yes, that's always true. The "co" in cosine means "complementary" as in the complementary angle, which adds to 90. So the sine of an angle is the cosine of the complementary angle.
C) No, the correct identity is sin(180-B)=sin B. Supplementary angles share the same sine.
D) Just like A, different triangle angles often have different cosines.
Answer: Choice B
12x15=18(3x+4)
180=54x+72
-72 -72
108=54x
/54 /54
2=x
X=2 the other person is a d0uche for answering like that so I answered instead of them
1) The domain is all the possible x values in the function so it would be [-4,4]
2) There are only 3 zeros shown on the graph and they are (-2, 0) (0, 0) (2, 0) the zeros are the value of x when y = 0.
3)The function is positive/Negative is asking for what x values make the y values positive aka interval notation. The function is positive if x = (0, 2) because 0 and 2 aren't included you use parentheses () instead of brackets []
The function is negative if x [-4, -2), (-2,0), (2,4]
<u>Answer:</u>
143°
option c is correct!
<u>Explanation:</u>
Given:
Two angles are supplementary:
One angle = 37°
We know if two angles are supplementary their sum is equal to 180°.
Let another angle be x°
= > 37° + x° = 180
= > x° = 143°
Therefore another angle is 143°.
