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3 years ago

How many 4-digit numbers can be formed using only the digits 9, 8 and 7?

Mathematics

1 answer:

Deffense [45]3 years ago

5 0

Answer:

There are 81 numbers

Step-by-step explanation:

Imagine that you have 4 boxes (one for each digit). In each box, you only have 3 choices for what digit you will do. You have to multiply all of the options (3*3*3*3) and you get 81.

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Answer:

Step-by-step explanation:

If so the inter quartile range = 58 - 9 = 49

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balu736 [363]

Answer:

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Step-by-step explanation:

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3 years ago

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

$\mathbf{Bars = 6}$

$\mathbf{Chocolate = 3}$

$\mathbf{Custard= 3}$

The total number of donuts in the box is:

$\mathbf{Total= 6 + 3 + 3}$

$\mathbf{Total= 12}$

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

$\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}$

So, we have:

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}$

Simplify

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}$

Multiply

$\mathbf{Pr = \frac{9}{132}}$

Divide

$\mathbf{Pr = 0.068}$

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068