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topjm [15]
3 years ago
10

The sum of two integers is -360. One of them is 60, then the other integer is

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0
2
CNN can. Nxkxmcidnxixnxksnxixnxixmficocc
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What is the first step to Solving Word Problems?
asambeis [7]
The first step in solving any word problem is to read the problem carefully.

Steps would be as follows:
1- Read the problem carefully
2- Identify what you are trying to find
3- Make a plan
4- Solve the problem
5- Check that your answer makes sense
8 0
3 years ago
Mr. Aba builds a circular patio with a diameter of 12 feet. He covers the patio with paving stones. The cost of the paving stone
Anettt [7]

Answer:

395.85

Step-by-step explanation:

If the diameter is 12, then the radius must be 6. Following the formula of pi: 2 * pi * radius, our result is 37.7. 37.7 * 10.50 is 395.85

I really hope this helps. My memory of circles and pi isn't the best.

8 0
2 years ago
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Write <br> 36/20<br> as a percentage.
mestny [16]
36/20 is 180% 

I hope this helps!

4 0
3 years ago
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Which two points are on the graph of M(a) = - 3/4a-12?
sertanlavr [38]

Answer:

(-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

Step-by-step explanation:

Here, the given expression is : M(a) = -\frac{3}{4} a-12

Here, let M(a)  = b

⇒The equation becomes b = -\frac{3}{4} a-12

Now, check for all the given points for (a,b)

<u>1) FOR (-9,0)</u>

RHS  is  -\frac{3}{4} (-9)-12  =   -5.25 \neq 0

Hence, (-9,0) is NOT on the graph.

<u>2) FOR (-16,0)</u>

Here, LHS = b = 0

andRHS  =   -\frac{3}{4} (-16)-12  = 12-12  = 0

Hence, LHS  =  RHS = 0  So, (-16,0) is  on the graph.

<u>3) FOR (0,12)</u>

Here, LHS = b = 12

RHS  is  -\frac{3}{4} (0)-12  =   -12  \neq 12

Hence, (0,12) is NOT on the graph.

<u>4) FOR (0,-12)</u>

Here, LHS = b = -12

RHS  is  -\frac{3}{4} (0)-12  =   -12

and LHS = RHS = -12

Hence, (0,-12) is  on the graph.

Hence, (-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

6 0
3 years ago
PLEASE HELP ASAPPPPP!!!!!!
atroni [7]
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