Answer:
Hello!
The statement is "if x and y are odd integers, then x + y is even"
and we want to prove it by contradiction.
Suppose that we have x and y odd numbers, and suppose that his addition is odd.
We know that an odd number can be writen as (2n +1) (and a even number can be written as 2n) where n is an integer number; then:
x = (2k + 1) and y = (2m + 1)
and x + y = j, where j is also a odd number, then j = (2h + 1)
then:
2k + 1 + 2m + 1 = 2h + 1
2(k + m) + 2 = 2h + 1
2(k + m) +1 = 2h
if k and m are integers, then k + m is also an integer, suppose that k + m = g
then 2g + 1 = 2h
this says that in odd number is equal to an even number, then we have a contradiction, and the addition of two odd numbers cant be an odd number.
Visible outline.
hope this helps
Answer:
Starting from root, recursively traverse the min-heap. Once we find a key with value less than our X, we know that every key in subtree of that key will be also smaller than our X. Otherwise, we should keep traversing.
Explanation:
The complexity of this algorithm will be O(N) where N is the number of keys in our min-heap.
Answer:
I can't tell you mine because that would be plagiarism but here's some ideas
Title Page. Every business report should feature a title page. ...
Summary. ...
Table of Contents. ...
Introduction. ...
Methods and Findings. ...
Conclusions and Recommendations. ...
References. ...
Appendices (If Applicable)
Explanation: Hope this helps:)
Answer:
yes, because of radiation
