Ms. Barnsley separates her class into two groups. She gives each student the same 25-question math quiz. Group A uses a calculat

Question

3 years ago

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Ms. Barnsley separates her class into two groups. She gives each student the same 25-question math quiz. Group A uses a calculat

or, while Group B does not. The table shows the completion times, in minutes, of students in each group.
Which statement is true about the distributions of completion times?

The students in Group A tended to complete the quiz in less time.
The median of Group A is greater than the median of Group B.
The means of both groups are about the same.
The standard deviation of Group B is less than the standard deviation of Group A.

Mathematics

2 answers:

Sindrei [870] · Answer 1 · 2022-09-01T06:03:35+03:00

Answer:

The median of Group A is greater than the median of Group B.

Step-by-step explanation:

Given

$\begin{array}{cccccccccc}{Group\ A} & 4.5 & 4.8 & 4.6 & 5.0 & 4.8 & 4.4 & 4.7 & 5.2 & 3.9 \ \\ {Group\ B} & 5.5 & 4.9 & 4.0 & 4.2 & 4.8 & 4.1 & 3.5 & 4.6 & 4.3 \ \end{array}$

Required

Which of the options is true

(a) Group A complete in less time

To do this, we calculate the average of both using:

$\bar x = \frac{\sum x}{n}$

Where

$n = 9$

So, we have:

$\bar x_A = \frac{4.5 + 4.8 + 4.6 + 5.0 + 4.8 + 4.4 + 4.7 + 5.2 + 3.9}{9}$

$\bar x_A = \frac{41.9}{9}$

$\bar x_A = 4.66$

$\bar x_B =\frac{5.5 + 4.9 + 4.0 + 4.2 + 4.8 + 4.1 + 3.5 + 4.6 + 4.3}{9}$

$\bar x_B =\frac{39.9}{9}$

$\bar x_B =4.43$

The average time of Group A is higher than that of B, this means that Group A spend more time, on average.

(b) Group A has a greater median

First, we sort the given data in ascending order

$\begin{array}{cccccccccc}{Group\ A} & 3.9 & 4.4 & 4.5 & 4.6 & 4.7 & 4.8 & 4.8 & 5.0 & 5.2 \ \\ {Group\ B} & 3.5 & 4.0 & 4.1 & 4.2 & 4.3 & 4.6 & 4.8 & 4.9 & 5.5 \ \end{array}$