Answer:
r = 225 Mil/h speed of the airplane in still air
Step-by-step explanation:
Then:
d is traveled distance and r the speed of the airplane in still air
so the first equation is for a 4 hours trip
as d = v*t
d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)
Second equation the trip back in 5 hours
d = 5 * ( r - 25 ) (2)
So we got a system of two equation and two unknown variables d and
r
We solve it by subtitution
from equation (1) d = 4r + 100
plugging in equation 2
4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h
And distance is :
d = 4*r + 100 ⇒ d = 4 * ( 225) + 100
d = 900 + 100
d = 1000 miles
<span>Let be A= 6x6 − x3y4 − 5xy5 and B= 4x5y + 2x3y4 + 5xy5
and when we do their difference, it is A - B =
6x6 − x3y4 − 5xy5 -( 4x5y + 2x3y4 + 5xy5)=6x6 − x3y4 − 5xy5 - 4x5y - 2x3y4 - 5xy5 = 6x6 - x3y4 - 2x3y4 - 5xy5 -4xy5 -5xy5=6x6 - 3x3y4 -14xy5, so the final solution is A - B =6x6 - 3x3y4 -14xy5, the degree of this is equal to the degree of - 3x3y4, and it is 3+4=7, the answer is
The difference has 3 terms and a degree of 7.</span>
This would depend on what you are asking for.
If you are adding the two numbers(which the word and is implying) you’re answer is 25 1/4.
You get this by finding a common denominator. In this case, that can be 4.
Turn 1/2 in to 2/4.
Next, you add 11 and 13 to get 24.
Then, you’ll add 2/4 and 3/4. You will get 1 1/4
Add 24 and 1 1/4. You have your answer of 25 1/4
Answer:
Quadratic
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