Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
Answer: The area of the square is increasing at a rate of 90.4 m2/min (square meters/minute)
Step-by-step explanation: Please see the attachments below
Answer:
2, 7, 27, 42
Step-by-step explanation:
y = 5*1 -3 =2
y = 5*2 -3 =7
y = 5*6 -3 = 27
y = 5*9 -3 = 42
Answer:
First number: 20
Second number: 30
Step-by-step explanation:
First#: x
Second#: y
Constraints:
x + y = 50
1/4x + 2/3y = 25
Isolate variable y:
x + y = 50
-1/4 (x + y = 50 )
-1/4x - 1/4y = -12.5
Add equations the two equations to eliminate x:
-1/4x - 1/4y = -12.5
1/4x + 2/3y = 25
_________________
5/12y = 12.5
5y = 150
y = 30
Substitution to find x:
x + y = 50
x + 30 = 50
x = 20
The equation would be 0.05x + 3.15 = 5.10
0.05x = 1.95 (subtraction)
x = 39 (division)
39 minutes
