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Maru [420]
3 years ago
7

a cell tower is located 2 miles east and 5 miles north of a small town. the cell tower has a coverage radius of 4 miles. A house

is located 7 miles north of the center of the town and is to the east of the cell tower. if the house lies on the boundary of the cell towers coverage, how far east of thr center of the town is the house?

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

The attached figure represents the explanation of the problem.

The distance between the house and the point B = 7 - 5 = 2

The distance between the house and the cell tower = 4

While the angle B is a right angle.

So, The distance between the house and the cell tower represents the hypotenuse

x and the distance between the house and the cell tower will be the legs

So, x = \sqrt{4^2 - 2^2} = \sqrt{16 - 4} =\sqrt{12} =3.464

The east distance between Town and House = 2 + x = 2 + 3.464 = 5.464 ≈ 5.5 miles

<u>So, The house will be located 5.5 miles east of the town</u>

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Donnavan is measuring the angles of a triangle. He measures the first two angles and gets 10° and 120°. What should be the measu
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0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store
g100num [7]

This question is incomplete, the complete question is;

The Millennium Falcon is chased by the Imperial Forces. The ship is moving at a speed of 0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20.00 plus 6.00% TAX. The cannon emits protons at a speed of 0.741 c with respect to the ship.

What is the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction?  0.911 ANS .

What is the velocity of the protons in the resting frame when the cannon is shot in the backward direction?

(Use positive sign for the forward direction, and negative for the backward direction.)

Answer:

A)

the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

B)

the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Step-by-step explanation:

Given that;

speed of ship u = 0.525C

speed of proton emission v = 0.741C

Now When Cannon is shot in Forward Direction

Relativistic speed S is Calculated as;

S = (u+v) / ((1 + (uv))/c²)

we substitute (0.525 + 0.741 )C / ((1 + (0.525 × 0.741) C)/c²)

the C² cancel each other

so we have

S = 1.266 / 1.389925

S = 0.9108 ≈ 0.911c

Therefore the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

When Cannon is shot in Backward  Direction

Relativistic speed S is Calculated as;

S = ( u – v ) / ( 1 – uv / c ²)

S =  (0.525 - 0.741) C / ((1 - (0.525 × 0.741) C)/c²)

the C² cancel each other

so S = -0.216 / 0.610975

S = -0.3535c

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Therefore the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

7 0
2 years ago
R = rmax (1-N/K) <br><br> i don’t understand??
butalik [34]

As given r = r(max)/2

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By substituting the values,

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You have to use following equation to get a value of N

r = r(max) ( 1- N/K)

N/k = 1 - r/r(max)

N/K = 1 - 0.5 = 0.5

N= 50 × 0.5 = 25

6 0
3 years ago
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