3x(2x+3y)
1. find a common multiple of either sides of the + sign...
3x
2. put it outside the brackets...
3x( )
3. find what you have to multiply the rest equation by to get the number...
2x x 3x = 6x squared
3y x 3x = 9xy
4. put it in the brackets...
3x(2x+3y)
Hope this helps :)
Answer:
i think option B is right
Answer:
Step-by-step explanation:
Firstly, we've to interchange the variables.
Solving for y
Adding 3 to both sides
Multiplying 2 to both sides
Taking cosine on both sides
Dividing both sides by y
Replace y by
=>
#11: First term is 2. Formula for the (n+1)th term is (previous term) + 3.
Thus, we have 2, 5, 8, 11, 14, ... This is an arithmetic sequence with common difference 3.
#12 First term is -4. Formula for the (n+1)th term is (previous term) + n^2.
Second term (n=2): -4 + (2^2) = 0
Third term (n=3) : 0+3^2 = 9
Fourth term (n=4): 9 + 4^2 = 25
Fifth term (n=5) : 25 + 5^2 = 50
Your correct answer should be 1/4