J because this is a quadratic function which is shaped like a u upward
If it’s to the nearest tenth it’s 1.4 if it’s the nearest hundredth 1.42
- The Midpoint of AB is (1,0).
Given that:
- In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).
To find:
So, according the question
We know that,
The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M (
).
Now from question,
We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.
So, we can say that
A is (3,1) or x₁ = 3 and y₁ = 1.
B (-1,-1) or x₂ = -1 and y₂ = -1.
∵ The coordinates of midpoint M (X,Y)
X = 
= 
= 2/2
X = 1.
And
Y = 
= 
= 0/2
Y = 0.
So, the midpoint of line AB is M (1,0)
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Answer:
(-2, -3), (1, 6), (2, 9) are plotted in the attached graph
Step-by-step explanation:
For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).
For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).
For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).
The graph is attached.