The formula for fractional exponents is ![\sqrt[n]{m} = x^{ \frac{m}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bm%7D%20%3D%20%20x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20)
For this particular problem the expression would be written as![\sqrt[2]{ x^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B%20x%5E%7B3%7D%20%7D%20)
For this particular problem the expression would be written as
Please help, i need it for a test, I'll give you brainliest :]
1 answer:
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Answer:
- Josh's book lands first
- Ben's lands about 0.648 seconds later
Step-by-step explanation:
Using the given equation for v=60 and s=40, the height of Ben's book is ...
h(t) = -16t² +60t +40
We want to find t when h(t) = 0, so we're looking for the solution to ....
0 = -16t² +60t +40
Using the quadratic formula, we find the positive value of t to be ...
t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277
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Similarly, the height of Josh's book is ...
0 = -16t² +48t +40
t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794
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The time before Josh's book lands is shorter by ...
4.3277 -3.6794 ≈ 0.6482 . . . . . seconds
Josh's book reaches the ground first, by about 0.648 seconds.
