Plz help 3 to 2 and 5 to 4

If the scale is 1/4"=1' then 2" will equal

4vir4ik [10]

1/4"=1'
2"=???'
2*1=2/4= 1/2'
your answer is 1/2

3 0

4 years ago

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Can the following question be considered a statistical question and why or why not?

Oxana [17]

Yes, it specifies the population

7 0

3 years ago

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A rectangle has length x and width x – 3. The area of the rectangle is 10 square meters. Complete the work to find the dimension

Tamiku [17]

Answer:

Step-by-step explanation:

Area of rectangle = Length × Width

The given rectangle has a length if x meters

The width of the triangle is (x-3) meters

The area of the rectangle is given as 10 square meters.

Area if rectangle = x(x-3) = 10

Multiplying each term in the parentheses,

x^2 -3x = 10

x^2 -3x -10 = 0

This is a quadratic equation

We will look for two numbers such that when they are multiplied, it will give us -10x^2 and when they are added, it will give -3x. It becomes

x^2 + 2x - 5x -10 = 0

x(x+2)-5(x+2) =0

( x + 2)(x-5) = 0

x = -2 or x = 5

The length of the rectangle cannot be negative so the length is 5 meters

Widith = x+3 = 5-3 = 2 meters

5 0

4 years ago

Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (

Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(c) (1, 0), (2, 0), (1, 3), (4, 3), (5, 7)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0

3 years ago

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A carpentry shop currently sells 66000 decoy ducks per year at a cost of 16 dollars each. In the previous year when they raised

Rus_ich [418]

Answer:

19 dollars

Step-by-step explanation:

<h2>Buckle up! This is a good one!</h2>

First we have to find the line that goes trough the two points. And it has the form :

$y=mx+b$

<em>m is often called the slope.</em>

Given the two points (66000, 16) and (51000, 21) we find m with this formula:

$m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\\m=\frac{21-16}{51000-66000} \\m=-\frac{5}{15000} \\m=-\frac{1}{3000}$

We pick the point (51000,21) and plug it into the equation of the line and we find b:

$y= mx + b\\21=(-\frac{1}{3000} )(51000)+b\\21=-17+b\\21+17=b=38$

<h3>And we have got our line equation</h3>

$y= -\frac{1}{3000}x + 38\\$

<u>Where x represents the quantity and y represents the price.</u>

<u />

<h2>The revenue</h2>

The revenue is price times quantity, since price is y and quantity is x, we get

$y=-\frac{1}{3000} x+38\\y*x=x*(-\frac{1}{3000} x+38)\\yx=-\frac{1}{3000} x^2+38x\\R(x)=-\frac{1}{3000} x^2+38x$

<h3>to maximize the revenue, we get the first derivative:</h3>

$R(x)=-\frac{1}{3000} x^2+38x\\R'(x)=-(2)\frac{1}{3000} x+38\\R'(x)=-\frac{2}{3000} x+38\\\\R'(x)=-\frac{1}{1500} x+38\\\\$

$R'(x)=-\frac{1}{1500} x+38=0\\38=\frac{1}{1500} x\\38*1500=x=57000$

So the quantity that maximizes revenue is 57000,

<h3>let's find out the price by plugging it into the equation:</h3>

$y= -\frac{1}{3000}x + 38\\y= -\frac{1}{3000}(57000) + 38\\y= -19 + 38\\y=19$

<h2>And there you go! 19 dollars is the price the carpentry shop should charge per decoy duck.</h2>

7 0

3 years ago