Answer:
We know that the area of the square of side length L is:
A = L*L = L^2
In this case, we know that the area is:
A = 128*x^3*y^4 cm^2
Then we have:
L^2 = 128*x^3*y^4 cm^2
If we apply the square root to both sides we get:
√(L^2) = √( 128*x^3*y^4 cm^2)
L = √(128)*(√x^3)*(√y^4) cm
Here we can replace:
(√x^3) = x^(3/2)
(√y^4) = y^(4/2) = y^2
Replacing these two, we get:
L = √(128)*x^(3/2)*y^2 cm
This is the simplest form of L.
There are many polynomials that fit the bill,
f(x)=a(x-r1)(x-r2)(x-r3)(x-r4) where a is any real number not equal to zero.
A simple one is when a=1.
where r1,r2,r3,r4 are the roots of the 4th degree polynomial.
Also note that for a polynomial with *real* coefficients, complex roots *always* come in conjugages, i.e. in the form a±bi [±=+/-]
So a polynomial would be:
f(x)=(x-(-4-5i))(x-(-4+5i))(x--2)(x--2)
or, simplifying
f(x)=(x+4+5i)(x+4-5i)(x+2)^2
=x^4+12x^3+77x^2+196x+164 [if you decide to expand]
It can’t be simplified more
He needs only one because 2 is bigger than 5/6
hope this helps and you rate me good
