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AleksandrR [38]
3 years ago
6

Form a polynomial f(x) with real coefficients having the given degree and zeros.

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0
There are many polynomials that fit the bill,
f(x)=a(x-r1)(x-r2)(x-r3)(x-r4)  where a is any real number not equal to zero.
A simple one is when a=1.
where r1,r2,r3,r4 are the roots of the 4th degree polynomial.
Also note that for a polynomial with *real* coefficients, complex roots *always* come in conjugages, i.e. in the form a±bi  [±=+/-]

So a polynomial would be:
f(x)=(x-(-4-5i))(x-(-4+5i))(x--2)(x--2)
or, simplifying
f(x)=(x+4+5i)(x+4-5i)(x+2)^2
=x^4+12x^3+77x^2+196x+164   [if you decide to expand]
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answer 74

4 0
3 years ago
f a rectangle has a perimeter of 70, a length of x and a width of x - 9, find the value of the length of the rectangle.
trasher [3.6K]

( x + (x  -  9))  \times 2 = 70 \\( 2x - 9) \times2= 70 \\ 4x - 18 = 70 \\ 4x = 70 + 18 = 88
x =  \frac{88}{4}  = 22
the length is 22


and the width is
22-9=17





good luck
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