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d1i1m1o1n [39]
3 years ago
14

In the third period of the periodic table, sodium is followed by magnesium, aluminum, silicon, and phosphorus. Which of these el

ements has the smallest atomic size?
A. sodium

B. magnesium

C. aluminum

D. silicon

E. phosphorus
Chemistry
2 answers:
AURORKA [14]3 years ago
6 0

Answer:

phosphorus

Explanation:

77julia77 [94]3 years ago
3 0

Answer:-

Phosphorus

Explanation:-

In the third period among the elements given, phosphorus is at the most right side among them in the periodic table.

We know that as we go from left to right in the periodic table, the atomic size decreases due to the increase in nuclear charge.

Hence phosphorus is the smallest among them

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Explanation:

From the question given above, the following data were obtained:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

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Next, we shall determine the molar mass of Ba₃(PO₄)₂. This can be obtained as follow:

Molar mass of Ba₃(PO₄)₂ = (137.3×3) + 2[31 + (4×16)]

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Number of mole of Ba₃(PO₄)₂ = 1.33 moles

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Mole = mass /Molar mass

1.33 = Mass of Ba₃(PO₄)₂ / 601.9

Cross multiply

Mass of Ba₃(PO₄)₂ = 1.33 × 601.9

Mass of Ba₃(PO₄)₂ = 801 g

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