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3 years ago

How many grams are there in 7.4x10^23 molecules of Na2SO4?

1 answer:

8 0

Molar mass Na2SO4 = 142.04 g/mol

142.04 g -------------- 6.02x10²³ atoms
?? g ------------------ 7.4x10²³ atoms

142.04 x ( 7.4x10²³) / 6.02x10²³

=> 174.60 g

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Answer:

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Explanation:

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Reduction half equation;

6Ag^+ + 6e -------> 6Ag

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Explanation:

We are given:

Mole fraction of saturated aqueous solution = 0.310

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To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

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Putting values in above equation, we get:

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To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}$

Where,

$n_{solute}$ = Moles of solute (non-electrolyte) = 0.310 moles

$W_{solvent}$ = Mass of solvent (water) = 12.42 g

Putting values in above equation, we get:

$\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m$

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