Answer:
The expression that is equivalent is 2 RootIndex 3 StartRoot 3 EndRoot
:
![2\sqrt[3]{3}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
Hi
As we have 24 Superscript one-third, this is
.
, therefore
, so
.
<h3>
Answer:</h3>
- -100x +100; 3
- 5x +81; 162
<h3>
Step-by-step explanation:</h3>
The distributive property is your friend. It tells you ...
a(b + c) = ab + ac
It can also be used to simplify the product of binomials (or other polynomials).
(a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2
(a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering
1. (x -10)^2 -x(x +80) = (x^2 -20x +100) +(-x^2 -80x)
= -100x +100 . . . . . . simplified form
For the purposes of calculation, it can be easier to factor out 100:
= 100 (1 -x)
Then for x = 0.97
= 100(1 -0.97) = 100(0.03) = 3
___
2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81
For x = 16.2, this is ...
5(16.2) +81 = 81 +81 = 162
_____
The purpose of the attachment is to show the evaluation is correct.
250 lunches are produced by the small business in last week.
<u>Step-by-step explanation:</u>
It is given that,
- y ⇒ the average cost per week.
- x ⇒ the number of lunches produced per week.
The function relating these two factors x and y is given as y = 2.1x + 75
- The cost of the last week is y = $600.
- The lunches made last week is x = unknown.
<u>To find the value of x :</u>
Substitute y= 600 in the given function,
⇒ 600 = 2.1x + 75
⇒ 2.1x = 600 - 75
⇒ x = 525 / 2.1
⇒ x = 250
Therefore, the lunches prepared last week is 250.
Answer:
m =-1.25
Step-by-step explanation:
5.2m + 5 = 2.9m – 3 – 4.1m
Combine like terms
5.2m + 5 = -1.2m – 3
Add 1.2m to each side
5.2m +1.2m +5 = -1.2m +1.2m -3
6.4m +5 = -3
Subtract 5 from each side
6.4m +5-5 = -3-5
6.4m = -8
Divide each side
6.4m/6.4 = -8/6.4
m =-1.25