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2 years ago

40 points need help please asap

Mathematics

1 answer:

Nat2105 [25]2 years ago

3 0

Answer:

1st one is not proportional

2nd one is: y is 5/6 times x

Hope this helps:)

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What is the value of 3-(-2)? A. 0 -5 B. -1 C. 0_1 D. 5

Irina18 [472]

3-(-2)
= 3-(-2)
= 3 + 2
= 5
The Answer is 5

3 0

2 years ago

The shortest side of a polygon of area 196 sq. in. is 4 in. long. Find the area of a similar polygon whose shortest side is 8 in

fenix001 [56]

The correct answer is: " 784 in² " .
_________________________________________
                  {or; write as: " 784 sq. inches " .}.
_________________________________________
      When the side is doubled (in this case, 4 is doubled; 4 * 2 = 8} ; the area is increased by 2² times; that is, by 4 times; so, the area is:
    (196 sq. in) * 4 =   784 sq inches .
_________________________________________

7 0

3 years ago

Read 2 more answers

How is this no solution? 9x+8y=15 9x+8y=30. Please show your work.

Brilliant_brown [7]

9x+8y=15
9x+8y=30

There can't be a solution because 9x+8y equal different things in both.

Hope this helps :)

7 0

3 years ago

Read 2 more answers

One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe

sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who disagree with the statement = $\frac{1812}{2625}$ = 0.69

n = sample of respondents = 2625

p = population proportion of people who disagree with statement

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ , $0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ ]

= [0.667 , 0.713]

Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

5 0

3 years ago

Prove that root 2 itrational number

Zolol [24]

Answer:

can you explain yourself more please

4 0

3 years ago