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ivanzaharov [21]
3 years ago
9

Lu is graphing the ordered pair (3, 5). Starting at the origin, what does she need to do?

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0

Answer:  

Lu needs to move the right 3 units and up 5 units.

Step-by-step explanation:

melomori [17]3 years ago
6 0
Lu needs to move the right 3 units and up 5 units.
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Can Someone answer this please
Vsevolod [243]

Answer:

So the scaling means that per every foot in real life, you have 2.4 centimeters, which means that the scale model would be 48 cm tall.

A. To find your answer, you would divide 48 by 1.2, which is 40. So your model would be 40 bottle caps tall

B. Same as A, all you have to do is divide 48 by 15.2, which would be about 3 popsicle sticks tall (rounded)

(Hope this helps)

Step-by-step explanation:

5 0
3 years ago
Show how to rewrite 1/5 with the denominator 10
AlladinOne [14]

The denominator is the bottom number.

To change the 5 to 10, you would multiply 5 by 2: 5 x 2 = 10

Because you multiplied the 5 by 2, you also need to multiply the numerator ( top number) by the same amount.

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So 1/5 = 2/10

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3 years ago
Problem PageQuestion It takes an older pump twice as long to drain a certain pool as it does a newer pump. Working together, it
umka2103 [35]

Answer:

It will take 6 hours for the new pump to drain the pool.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

Let the rate of new pump is given as x=W/t_1

Let the rate of the old pump is given as y=W/t_2

it is given that the time t_2=2t_1

So by substituting the values of t_2 in the rate equation of y

y=W/2t_1

y=(W/t_1*2)=x/2

Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes

x+y=W/4

x+x/2=W/4

3x/2=W/4

As x=W/t_1

3W/2t_1=W/4

Now as W is same on both sides so

3/2t_1=1/4

12=2t_1

t_1=6 hours

So it will take 6 hours for the new pump to drain the pool.

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4 years ago
I need help in Elementary Statistics
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melisa1 [442]

Answer: A, C, E.

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