Answer:
broken pieces of glass from a window can't form a shadow.
Explanation:
the reason is that shadow is formed only when light rays hits an opaque object, which doesn't let light to pass through it, but glass is a transparent object, hence light rays passes through it forming no shadow..
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
k = 3.5 N/m
Explanation:
It is given that the time period the bob in pendulum is the same as its time period in spring mass system:
![Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}](https://tex.z-dn.net/?f=Time%5C%20Period%5C%20of%5C%20Pendulum%20%3D%20Time%5C%20Period%5C%20of%5C%20Spring-Mass%5C%20System%5C%5C2%5Cpi%20%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%7D%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bm%7D%7Bk%7D)
![\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}](https://tex.z-dn.net/?f=%5Cfrac%7Bl%7D%7Bg%7D%20%3D%20%5Cfrac%7Bm%7D%7Bk%7D%5C%5C%5C%5C%20k%20%3D%20g%5Cfrac%7Bm%7D%7Bl%7D)
where,
k = spring constant = ?
g = acceleration due to gravity = 9.81 m/s²
m = mass of bob = 125 g = 0.125 kg
l = length of pendulum = 35 cm = 0.35 m
Therefore,
![k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\](https://tex.z-dn.net/?f=k%20%3D%20%289.81%5C%20m%2Fs%5E2%29%28%5Cfrac%7B0.125%5C%20kg%7D%7B0.35%5C%20m%7D%29%5C%5C%5C%5C)
<u>k = 3.5 N/m</u>
Answer: Symbol is I and unit A
Explanation: A represents Amperes
HOPE THIS HELPS!!!!!!!!
Answer:
208.33 W
141.26626 seconds
Explanation:
E = Energy = ![6\times 10^6\ J](https://tex.z-dn.net/?f=6%5Ctimes%2010%5E6%5C%20J)
t = Time taken = 8 h
m = Mass = 2000 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height of platform = 1.5 m
Power is obtained when we divide energy by time
![P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BE%7D%7Bt%7D%5C%5C%5CRightarrow%20P%3D%5Cfrac%7B6%5Ctimes%2010%5E6%7D%7B8%5Ctimes%2060%5Ctimes%2060%7D%5C%5C%5CRightarrow%20P%3D208.33%5C%20W)
The average useful power output of the person is 208.33 W
The energy in the next part would be the potential energy
The time taken would be
![t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7BE%7D%7BP%7D%5C%5C%5CRightarrow%20t%3D%5Cfrac%7Bmgh%7D%7B208.33%7D%5C%5C%5CRightarrow%20t%3D%5Cfrac%7B2000%5Ctimes%209.81%5Ctimes%201.5%7D%7B208.33%7D%5C%5C%5CRightarrow%20t%3D141.26626%5C%20s)
The time taken to lift the load is 141.26626 seconds