The answer is A. Reactivity
hope this helps
A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. The change in the electric potential energy of the proton-field system when the proton travels to x = 2.50m is -3.40 × 10⁻¹⁶ J (Option B)
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How is the change in electric potential energy of the proton-field system calculated?</h3>
- Work done on the proton =Negative of the change in the electric potential energy of the proton field
- In the given case, W = -qΔV
- -W = qΔV
- = qEcosθ
- Therefore, work done on the proton = -e(8.50× N/C)(2.5m)(1)
- = -3.40× J
- Any change in the potential energy indicates the work done by the proton.
- Therefore the positive sign shows that the potential energy increases when the proton does the work.
- The negative sign shows that the potential energy decreases when the proton does the work.
To learn more about electric potential energy, refer
brainly.com/question/14306881
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Answer:
201.76266192 m
Explanation:
Distance traveled in the horizontal direction = 153 m
In the vertical direction the distance traveled
Total distance from pythagoras theorem
The total distance the boat will travel to reach the opposite shore is 201.76266192 m
Answer:
A=ACCELERATION = -4 m/s^2
B=DISTANCE= 72 m
Explanation:
Solving for the acceleration of the car
A= (10 m/s-30 m/s) / 5s
A= -20 m/s / 5s
A= -4 m/s^2
Solving for the distance traveled after the third second
D= v1 * t + 1/2at^2
D= 30 m/s * 3 s + -2m/s^2 * (3s)^2
D= 90 m + - 18 m
D = 72 m