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Valentin [98]
3 years ago
13

How do you calculate an object's displacement?

Physics
2 answers:
algol [13]3 years ago
4 0

Answer:

Displacement can be calculated by measuring the final distance away from a point, and then subtracting the initial distance. Displacement is key when determining velocity (which is also a vector). Velocity = displacement/time whereas speed is distance/time.

Explanation:

andrezito [222]3 years ago
3 0

Answer:

We can use equations of motion

s = ut +  \frac{1}{2} at {}^{2}

v {}^{2}  =  {u}^{2}  + 2as \:

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4 0
3 years ago
Read 2 more answers
Which of these is equivalent to the law of conservation of energy?
Korolek [52]
The Law of the Conservation of Energy is stating that the total mechanical energy is always conserved or in simpler terms, not used or saved.
7 0
3 years ago
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what is the total distance traveled by a bike rider who rides for three hours at 40 km/hr and then two more hours at 50 km/hr?
marta [7]

Answer:

220 km

Explanation:

3 hours at 40 km/hr

40 km = 1 hour

40 km times 3 = 120 km

2 hours at 50 km/hr

50 km = 1 hour

50 times 2 = 100 km

Total distance

120 km + 100 km = 220 km

4 0
3 years ago
"Nuclear fission is the splitting of electrons in the outer shell of an atom." True or False?
sweet-ann [11.9K]

Answer:

The correct answer is:

False

Explanation:

Nuclear fission is the splitting of nucleus of an atom which results in the emission of high amount of energy.

<u>Example:</u>

Heavy atom (i.e. uranium) when bombarded with neutrons, its nucleus split into smaller lighter weight nuclei and release a huge amount of energy. (Nuclear fission also takes place without neutrons i.e. in the form of radioactive decay (the process in which an unstable nucleus of an atom releases energy in the form of radiation)).

3 0
3 years ago
A certain instant camera determines the distance to the subject by sending out a sound wave and measuring the time needed for th
valentinak56 [21]
The total distance covered by the sound wave is twice the distance between the camera and the subject (because the wave has to reach the subject and then travel back to the camera), so 2L, where L=3.42 m. The speed of sound is v=343 m/s. It is a uniform linear motion, so we can use the basic relationship between space (S), time (t) and velocity (v) to find the time the wave needs to return to the camera:
t= \frac{S}{v}= \frac{2L}{v}= \frac{2\cdot 3.42 m}{343 m/s}=0.020 s
6 0
3 years ago
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