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2 years ago

How do you calculate an object's displacement?

Physics

2 answers:

algol [13]2 years ago

4 0

Answer:

Displacement can be calculated by measuring the final distance away from a point, and then subtracting the initial distance. Displacement is key when determining velocity (which is also a vector). Velocity = displacement/time whereas speed is distance/time.

Explanation:

andrezito [222]2 years ago

3 0

Answer:

We can use equations of motion

$s = ut + \frac{1}{2} at {}^{2}$

$v {}^{2} = {u}^{2} + 2as \:$

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Help i hope this actually works

KIM [24]

Answer:

it does tbh.

Explanation:

6 0

2 years ago

Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would

Tatiana [17]

Answer:

<h3>The power of headlight in series connection is 29.64 W</h3>

Explanation:

Given :

Power of headlight $P_{1} = 30$ W

Power of starter $P_{2} = 2500$ W

Voltage of headlight and starter $V = 12$ V

From equation of power,

$P = \frac{V^{2} }{R}$

$R = \frac{V^{2} }{P}$

For finding the resistance of headlight and starter,

⇒ For headlight,

$R_{1} = \frac{144}{30} = 4.8$ Ω

⇒ For starter,

$R_{2} = \frac{144}{2500} = 0.057$ Ω

Since equivalent resistance,

$R_{eq} = R_{1} + R_{2} + ........$

$R_{eq} = 4.8 +0.057 = 4.857$ Ω

So power in series is given by,

$P_{s } = \frac{V^{2} }{R_{eq} } = \frac{144}{4.857}$

$P_{s } = 29.64$ W

8 0

2 years ago

A positive charge Q is placed at the origin. Four other positive charges are placed on a circle in the x-y plane centered on Q a

Shkiper50 [21]

1. <span>FX = 0 since the bottom charges are symmetrical about the y axis and the top charge is aligned with the y-axis
3. </span><span>FY > 0 since the bottom charges do not equate the top charge. The bottom charges have horizontal components which is less than q and adding them all, will not result to 3q.</span>

5 0

2 years ago

Naturally occurring element X exists in three isotopic forms: X-28 (27.977 amu, 92.23% abundance), X-29 (28.976 amu, 4.67% abund

vova2212 [387]

Answer:

C. 28.09 amu

Explanation:

The natural occurring element exist in 3 isotopic forms: namely X-28 (27.977 amu, 92.23% abundance), X-29 (28.976 amu, 4.67% abundance) and X-30 (29.974 amu, 3.10% abundance).

The atomic weight of elements depends on the isotopic abundance. If you know the fractional abundance and the mass of the isotopes the atomic weight can be computed.

The atomic weight is computed as follows:

atomic weight = mass of X-28 × fractional abundance + mass of X-29 × fractional abundance + mass of X-30 × fractional abundance

atomic weight = 27.977 × 0.9223 + 28.976 × 0.0467 + 29.974 × 0.0310

atomic weight = 25.8031871 + 1.3531792 + 0.929194

atomic weight = 28.0855603 amu

To 2 decimal place atomic weight = 28.09 amu

6 0

2 years ago

1. A 25.35-g piece of iron absorbs 1562.75 Joules of heat energy, and its temperature

Lera25 [3.4K]

Answer:

Q = C M T where C is the specific, M the mass, T the temperature change

Note 1 cal = 4.19 Joules

1562.75 J / (4.19 J/cal) = 378 cal

C = Q / (M * T) = 378 cal / (25.35 g * 155 deg C)

C = .096 cal / g deg C

8 0

1 year ago