Answer:
K' = 1777.777 J
Explanation:
Given that
m = 40 kg
v= 15 m/s
K=1000
Given that kinetic energy(K) varies with mass(m) and velocity(v)
K= C(mv²)
Where
C= Constant
m=mass
v=velocity
When
m = 40 kg ,v= 15 m/s ,K=1000
K= C(mv²)
1000 = C( 40 x 15²)
C=0.111111
When m = 40 kg and v= 20 m/s
K' = C(mv²)
K= 0.1111 x (40 x 20²)
K' = 1777.777 J
The only correct statement on that list is <em>choice-C</em>: If a positively charged rod is brought close to a positively charged object, the two objects will repel.
Because of BOMDAS, you do the multiplication first.
(3.0x10) - 4 - (1.7x10) - 6
= 30 - 4 - 17 - 6
= 3
C. Slamming on the brakes to come to a stop at a stop sign. Here you are Decelerating.
Answer:
Potential energy, E = 25 mgh
Explanation:
Given that,
Mass of the object, m = 5 m
It is lifted to a height of, h = 5 h
It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :
E = 25 mgh
So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.