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2 years ago

7x

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

5 0

wha did I jus readsrry I jus need mo pointssssssssss

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What's the awnser to the one about Isabella

Irina18 [472]

I cant even see the picture clearly

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3 years ago

One Friday night, two large groups of people called Weston Taxi Service. The first group requested 2 sedans and 1 minivan, which

muminat

Answer:

Sedan: 4 passengers

Minivan: 6 passengers

Step-by-step explanation:

We can write the following system of equations:

$\begin{cases}2s+1m=14 \\2s+2m=20\end{cases}$ , where $s$ represents the number of people a sedan can seat and $m$ represents the number of people a minivan can seat.

Subtracting the first equation from the second, we have:

$2s+2m-(2s+1m)=20-14,\\\\m=6$

Now plug in $m=6$ in any of the equations to solve for $s$ :

$2s+1(6)=14, \\2s=8, \\s=4$

Verify that the solution pair $(4, 6)$ works:

$2(4)+1(6)=14\: \checkmark \\2(4)+2(6)=20 \: \checkmark$

Therefore, a sedan can hold 4 passengers and a minivan can hold 6 passengers.

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3 years ago

Henry is fishing from a small boat. His fishing hook is in the water 8 meters directly below his boat. A fish is swimming at the

Angelina_Jolie [31]

Answer: 17

Step-by-step explanation:

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2 years ago

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$