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The sum of two numbers is 51. If one fourth of one number exceeds one fifth of another number by 6, which of the following is th

jeka57 [31]

Let x=smaller number
Then x+5=larger number
Now we are told the following:
1/5(x+x+5)=x-5 multiply each side by 5
x+x+5=5x-25 subtract 5x and also 5 from both sides
x+x+5-5-5x=5x-5x-25-5 collect like terms
-3x=-30 divide both sides by -3
x=10 smaller number
x+5=10+5=15 larger number
CK
1/5(10+15)=10-5
1/5(25)=10-5
5=5

3 0

3 years ago

Ill give brainliest and 45 points

Ne4ueva [31]

Answer:

B. 2 3/4 lbs

Step-by-step explanation:

there ar 16 ticks on a scale, the pointer is on 12, meaning it is 12/16, whihc is answer b

4 0

2 years ago

Read 2 more answers

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one

Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that $p = 0.75$

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

$P(X = 6) + P(X < 6) = 1$