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Reika [66]
3 years ago
15

PLS HELP ASAP! GIVING BRAINLIST

Mathematics
2 answers:
garri49 [273]3 years ago
3 0

Answer:

8.48528137424

Step-by-step explanation:

zvonat [6]3 years ago
3 0

Answer:

6√2

Step-by-step explanation:

√72=8.48

6√2=8.48

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8.35 &lt; 3x +18.75<br> Pls help
zzz [600]

Step-by-step explanation:

8.35 < 3x + 18.75

3x + 18.75 > 8.35

3x > 8.35 - 18.75

3x > -10.4

x > -3.47

5 0
3 years ago
The mean age of 5 people in a room is 32 years. A person enters the room. The mean age is now 34. What is the age of the person
nikdorinn [45]
The age of the person is 36 :) hoped this helped
8 0
3 years ago
The Florida Fish and Wildlife Conversation Commission (FWC) plans to hire hunters to kill the Burmese python, an invasive specie
andrew-mc [135]

Complete Question

The complete question is shown on the first uploaded image

Answer:

FWOC should hire 70,000 hunters to completely remove the python in the area

Step-by-step explanation:

From the question we are given that the Initial Pythons P_o= 100,000

And the final python   P_f =100,000+\frac{P}{10,000}(100,000-P)

                                      P_f = 100,000 + 10P -\frac{P^2}{10,000}

                For Max Number of  Python

                                        => \frac{dP_f}{dP} = 0

                                        => \frac{dP_f}{dP} =  100,000 -2P = 0

                                       =>   P = 50,000

Hence the maximum number of pythons Max_P =100,000 +\frac{50,000}{10,000} (50,000)

                                                                               =350,000

Using Mathematical relations

              from the Question

     5 python is killed by  = 1 hunter

      1 python is killed by =  \frac{1}{5}  \ hunters

      350 , 000 pythons are killed by  =   \frac{350,000}{5}

                                                             = 70,000 \ hunters

   

                                         

3 0
3 years ago
Anybody who knows Pre Calc?? My last offer here<br> Solution PLS!
4vir4ik [10]

Answers:

  • true speed = 26.935546 knots
  • true bearing = 102.265139 degrees

The values are approximate. Round them however you need to.

====================================================

Explanation:

The diagram you have drawn is correct if you're only considering one current. Specifically current #1 which has the bearing of 290 degrees moving at 25 knots.

The red angle is 290 degrees. The remaining portion that is needed to get a full 360 degrees is 360-290 = 70. This adds to the blue portion in quadrant 1, which is 90, and we get 70+90 = 160. So the blue angle is 160 degrees.

The vector for current #1 is <25*cos(160), 25*sin(160)>

This approximates to <-23.4923155, 8.5505036>

All of this is for current #1.

------------

Vector #2 is much more simple in terms that there aren't messy decimal approximations here. The direction is due north, which means that the vector is pointing straight up toward 90 degrees.

We can then say: <12*cos(90), 12*sin(90)> = <12*0, 12*1> = <0, 12>

Vector #2 is <0,12>

When you wrote <12,0>, you were on the right track, but you had the coordinates swapped in the wrong order.

----------

Then we have to account for a wind going 4 knots in the southwest direction. This is at the angle 225 degrees (we rotate 180 degrees plus another 45 to get 225). So,

vector #3 = <4*cos(225), 4*sin(225)> = <-2.8284271, -2.8284271>

This vector's coordinates are approximate

---------

To recap everything so far, vectors 1 through 3 are the following

  • p = <-23.4923155, 8.5505036>
  • q = <0, 12>
  • r = <-2.8284271, -2.8284271>

I'm using variables to represent the vectors at this point, so we can then add them up to get...

s = p+q+r

s = <-23.4923155, 8.5505036> + <0,12> + <-2.8284271, -2.8284271>

s = <-23.4923155+0+(-2.8284271), 8.5505036+0+(-2.8284271)>

s = <-26.3207426, 5.7220765>

Vector s represents the sum of the three vectors p, q, and r. The two currents and the wind ultimately combine together to push the boat in the direction and along the length of vector s.

----------------------

Now that we know the coordinates of vector s, we use them to find the true speed and true bearing of the boat.

speed = sqrt(a^2 + b^2)

speed = sqrt( (-26.3207426)^2 + (5.7220765)^2 )

speed = 26.935546 knots, which is approximate

angle = arctan(b/a)

angle = arctan(5.7220765/(-26.3207426))

angle = -12.265139

Add 360 to this angle to find that we get to the coterminal angle of -12.265139+360 = 347.734861 degrees

This angle is in quadrant 4, which is the southeast quadrant. If we rotate another 360-347.734861 = 12.265139 degrees, going counterclockwise, then we'll face directly east. Then another 90 degree counterclockwise rotation has us face directly north.

In total, the true bearing is approximately 90+12.265139 = 102.265139 degrees

So we'll start aiming north, and then rotate roughly 102.265139 degrees toward the east to get to the true bearing.

4 0
3 years ago
The board of examiners that administers the real estate broker's examination in a certain state found that the mean score on the
Goshia [24]

Answer:

The passing score is 645.2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 553, \sigma = 72

If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 553}{72}

X - 553 = 1.28*72

X = 645.2

The passing score is 645.2

6 0
3 years ago
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