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BigorU [14]
2 years ago
5

(?) what is the relationship between the 81 degree angle ? what is the measure of this angle ?

Mathematics
2 answers:
swat322 years ago
7 0

Answer:

<u>A.</u> They are corresponding and vertically opposite

<u>B.</u> <u>Rigid Motion:</u>

Any way of moving all the points in the plane such that. a) the relative distance between points stays the same and. b) the relative position of the points stays the same. There are four types of rigid motions that we will consider: translation , rotation, reflection, and glide reflection.

<u>C:</u> 81

Step-by-step explanation:

valentina_108 [34]2 years ago
5 0
Here the angle opposite to the 81 degree will also be 81 degree ( vertically opposite angles)
Now the angle opposite to x degree will be 82 (alternate angles)
And lastly x degree is equals to 81 degree( vertically opposite angle)
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A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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Answer:

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jekas [21]

Using the given functions, it is found that:

  • Lower total cost at Jump-n-Play: 40, 64.
  • Lower total cost at Bounce house: 28, 8, 30.
  • Same total cost at both locations: 32.

<h3>What are the cost functions?</h3>

For n visits to Jump-n-play, the cost is:

J(n) = 189 + 3n.

For n visits to Bounce Word, the cost is:

B(n) = 125 + 5n.

Comparing them, we have that:

J(n) < B(n)

189 + 3n < 125 + 5n

64 < 2n

n > 32

Hence:

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  • For more than 32 visits, the cost at Jump-n-play is lower.

Hence:

  • Lower total cost at Jump-n-Play: 40, 64.
  • Lower total cost at Bounce house: 28, 8, 30.
  • Same total cost at both locations: 32.

More can be learned about functions at brainly.com/question/25537936

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