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alexdok [17]
4 years ago
14

What is wrong with this question if K =4 then 3k+5=39

Mathematics
2 answers:
Virty [35]4 years ago
7 0
3k+5=-39

3(4)+5=-39
12+5=-39
17=-39

well 17 doesnt equal -39. the variable provided is wrong!

3k+5=-39
3k = -44
k = -14.66666667

so .... k should have been solved for instead of just plugging in a number!
kotegsom [21]4 years ago
4 0
You can tell it's wrong by plugging in 4 for K like so:
3(4) + 5 = 39

12 + 5 = 39

17 = 39

By looking at this you can tell it's false because 17 is not equal to 39.


I hope this helps! Feel free to let me know if you have any questions!

- mathwizzard3

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Now, lets see the last coordinate.

A primitive of sec²(t) is tan(t)+c (you can check this by derivating tan(t) = sin(t)/cos(t) using the divition rule and the property that cos²(t)+sin²(t) = 1 for all t). Since in its third coordinate r(0) is also 2, then we have that

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