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alexdok [17]
3 years ago
14

What is wrong with this question if K =4 then 3k+5=39

Mathematics
2 answers:
Virty [35]3 years ago
7 0
3k+5=-39

3(4)+5=-39
12+5=-39
17=-39

well 17 doesnt equal -39. the variable provided is wrong!

3k+5=-39
3k = -44
k = -14.66666667

so .... k should have been solved for instead of just plugging in a number!
kotegsom [21]3 years ago
4 0
You can tell it's wrong by plugging in 4 for K like so:
3(4) + 5 = 39

12 + 5 = 39

17 = 39

By looking at this you can tell it's false because 17 is not equal to 39.


I hope this helps! Feel free to let me know if you have any questions!

- mathwizzard3

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Enter the expression using exponents. 11 × 11 × 11 × 11 × 11 =
Alla [95]

Answer:

the answer should be 11^{5} or 11^5

Explanation:

Since there are five 11 in the equation, the answer should be 11^{5} or 11^5

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6 0
3 years ago
If DA = 6 and MD = 4, what is the length of DK?
Leto [7]

Answer:

DK = 9

Step-by-step explanation:

In triangle AMD,

h² = p² + b²

or, h² = 6² + 4²

or, h²= 36 + 16

so, h² = 52

so, AM² = 52

Take x as reference angle,

cos²x = 16/52

Now,

In triangle, AMK,

Taking x as reference angle,

cos²x = b²/h²

cos²x = AM²/MK²

or, cos²x = 52/MK²

Now,

cos²x = 16/52 = 52/MK²

or,

16/52 = 52/MK²

or, 16MK² = 2704

or, MK² = 2704/16

or, MK² = 169

so, MK = 13

Now,

DK = MK - MD

or, DK = 13 - 4

so, DK = 9

3 0
3 years ago
The growth of a city is described by the population functionwhereis the initial population of the city, t is the time in years,
mamaluj [8]

Complete question:

The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at

Answer:

27,800

Step-by-step explanation:

We need to obtain the initial population(P0) and constant value (k)

Population function : p(t) = P0e^kt

At t = 0, population = 19,000

19,000 = P0e^(k*0)

19,000 = P0 * e^0

19000 = P0 * 1

19000 = P0

Hence, initial population = 19,000

At t = 3; population = 23,000

23,000 = 19000e^(k*3)

23000 = 19000 * e^3k

e^3k = 23000/ 19000

e^3k = 1.2105263

Take the ln

3k = ln(1.2105263)

k = 0.1910552 / 3

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At t = 6

p(t) = P0e^kt

p(6) = 19000 * e^(0.0636850 * 6)

P(6) = 19000 * e^0.3821104

P(6) = 19000 * 1.4653739

P(6) = 27842.104

27,800 ( nearest whole number)

3 0
3 years ago
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