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2 years ago

Please help 10 minutes left

Mathematics

1 answer:

Maksim231197 [3]2 years ago

6 0

Answer:

I belive the answer is D

Step-by-step explanation:

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ABCD is a parallelogram. Find the values of x and y. Solve for the value of z, if z=x−y.

slava [35]

Answer:

Step-by-step explanation:

Parallel and opposite sides of a parallelogram are equal. Hence, we can say:

x + 30 = 2x - 10

and

2y-10 = y +10

Solving first one, we get:

x + 30 = 2x - 10

30+10 = x

x = 40

Also

2y - 10 = y + 10

y = 10 + 10

y = 20

Now, z = x - y, so

z = 40 - 20 = 20

Answer C is right.

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2 years ago

Rochy deposited $400 in her checking account. She wrote a check for $400 to pay for her car note. Then , she made another deposi

AnnZ [28]

Answer:

$500

Step-by-step explanation:

She pick in $400, she took that $400 out so she would then have $0

She then inserted $500 back in with no money previously

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3 years ago

Read 2 more answers

Graph the piecewise function??

Alik [6]

Check the picture below.

notice, the dashed line is the "continuation" of the graph, however, for the constraints in the piece-wise, is excluded.

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3 years ago

The Barber are keeping track of their family energy costs. It costs the Barbers $0.16 per week to run their dishwasher. How much

rosijanka [135]

Answer:

It will cost them $8.32 to run their dishwasher for 52 weeks.

Step-by-step explanation:

With the information provided, you can say that the cost to run the dishwasher is equal to the cost per week for the number of weeks, which would be:

Total cost=$0.16*number of weeks

Since you want to determine the cost to run the dishwasher for 52 weeks, you can replace the number of weeks in the formula to get the answer:

Total cost=$0.16*52

Total cost=$8.32

According to this, the answer is that it will cost them $8.32 to run their dishwasher for 52 weeks.

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2 years ago

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

7 0

3 years ago