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pav-90 [236]
3 years ago
7

Solve the system need help ASAP

Mathematics
1 answer:
Allisa [31]3 years ago
7 0

Answer:

jd77xxxujxujx is a identity theft system to use for all the essential things 45.0

Step-by-step explanation:

ij xiijhhb I think

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An item that originally cost $12 was on clearance Alford $3.60 what is the percentage of the discount
soldi70 [24.7K]

Answer:

she has hdu 7match the inequalities with the graphs

6 0
3 years ago
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What is the solution to the system of equations? (7, 4) (7, startfraction 13 over 3 endfraction) (8, startfraction 14 over 3 end
miss Akunina [59]

The points are (7, 13/3).

Lets simplify the equation,

The equation of first line: y = 1/3 x + 2

the equation of second line: y= 4/3x - 5

Solve the system of equations by elimination,

Multiply equation A by -4 both sides

-4y = -4(1/3x +2)

-4y = -4/3x-8

After eliminating the equation we get,

y = 13/3

So now have to find x

13/3 = 1/3x + 2

Lets multiply above by 3
x = 13-6

x = 7.

Hence the points are (7, 13/3)

Learn more about Quadratic Equation on:

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5 0
2 years ago
a garage doors 15 feet wide and 6 feet high it is painted white except for a rectangular panel 1 foot high and 9 feet wide what
umka2103 [35]
15 x 6 = 90 (total area of the door) 
1 x 9 = 9 (area of the panel) 

90 - 9 = 81 (area of the white portion)
4 0
3 years ago
What is 9/10 + 7/100?
svet-max [94.6K]

9/10 + 7/100

find the common denominator for 9/10 which is 100

multiply by 10 for 9/10

(9)(10)=90

(10)(10)=100

90/100+7/100

Answer:

97/100

8 0
3 years ago
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In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 25
Anastaziya [24]

Answer:

16 faults

Step-by-step explanation:

<u><em>The correct question is</em></u>

In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 2/5 of all her first serves. If 1/3 of her first serves were returned, how many of the tennis player's first serves were faults?

Let

x -----> the number of all her first servers

y ----> the number of first services returned

z ---> the number of first services faults

we know that

The number of aces plus the number of returned plus the number of faults must be equal to the number of all her first services

so

x=24+y+z

step 1

Find out the number of all her first servers

we have that

24=\frac{2}{5}x

Solve for x

x=24(5)/2\\x=60\ first\ services

step 2

Find out the number of first services returned

y=\frac{1}{3}x

substitute the value of x

y=\frac{1}{3}(60)=20\ returned

step 3

Find out the number of first services faults

x=24+y+z

we have

x=60\\y=20

substitute and solve for z

60=24+20+z

60=44+z

z=16\ faults

6 0
3 years ago
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