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Drupady [299]
2 years ago
7

Suppose you have 76 feet for a regular dog pen the function A= 38x-x^2 where x= width gives you the maximum area what is the max

imum area round the nearest tenth as necessary
A= width=19ft,area =361ft^2

B= width=38ft,area=760ft^2

C= width=38ft,area =361^2

D= width=19ft,area=1083ft^2
Mathematics
1 answer:
trasher [3.6K]2 years ago
6 0
A I believe. width= 19ft, area 361ft^2
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What is the ordered pair of y=4.5x
garri49 [273]

Answer:(1,1)

Step-by-step explanation:

y=4.5x

x=y/4.5

put value of x

y=4.5(y/4.5)

y=y

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3 years ago
Somebody help me please.I am taking algebra in freshman high school
ad-work [718]
The pattern is the amount you need to add increases by 2 each time. Ex. 1+1=2 2+3=5 3+5=8
8 0
3 years ago
Gulf gully and jump rope road are a pretty far distance.If the scale for the map is 0.5 inches=2.3 miles,what is the actual dist
Nezavi [6.7K]

Answer:

12 cm = 21.62 miles

6 cm = 11.04 miles

Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of \frac{map}{real world} and simplify.

We know \frac{map}{real world}=\frac{0.5in}{2.3 miles}. We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write \frac{4.7in}{xmiles} and  \frac{2.4in}{xmiles}

We set them equal.

\frac{0.5}{2.3}=\frac{4.7}{x}

and

\frac{0.5}{2.3}=\frac{2.4}{x}

To solve each proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

2.3(4.7)=0.5(x)\\10.81=0.5x\\\frac{10.81}{0.5}=\frac{0.5x}{0.5} \\21.62 miles=x

and

2.3(2.4)=0.5(x)\\5.52=0.5x\\\frac{5.52}{0.5}=\frac{0.5x}{0.5} \\11.04 miles=x

8 0
3 years ago
P(t) = 2ť + 10<br> n(t) = 4<br> What’s the function (p+n) (t)?
Evgen [1.6K]

Answer:

\boxed{\sf (p + n)(t) = 2t + 14}

Given:

\sf p(t) = 2t + 10 \\ \sf n(t) = 4

To find:

\sf (f + g)(x) = f(x) + g(x)

Step-by-step explanation:

\sf \implies(f + g)x = f(x) + g(x) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (2t + 10) + ( 4) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 2t + 10 + 4 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 2t + 14

7 0
3 years ago
Which of the following describes the end behavior over the domain of the square root function graphed above? Please HELP!!!!!!!!
PilotLPTM [1.2K]
Short Answer A
Comment

It's a good thing that the domain is confined or the graph is. That function is undefined if x < - 3 

At exactly x = - 3, f(x) = 0 and that's your starting point.

So look what happens to this graph. If x = 0, f(0) =  y = 3. So we are starting to see that as x get's larger so does f(x). The graph tells us that x = 0 is bigger than x = - 3.

Let's keep on plugging things in.
As x increases to 5, f(5) = 5. x = 5 is larger than x = 0, and f(5) > 3.

One more and then we'll start drawing conclusions. If x = 9 then f(9) = y =  6. 
x = 9 is larger than x = 5. f(9) = 6 is just larger than f(5) which is 5

OK I think we should be ready to look at answers. There's nothing there that makes the answer anything but a. Let's find out what the problem is with the rest of the choices.

B
The problem with B is that as x increases, f(x) does not decrease. We didn't find one example of that. So B is wrong.

C
C has exactly the same problem as B. 

D
The second statement in D is incorrect. As x increases f(x) never decreases. No example showed that.

The answer is A <<<< Answer.
8 0
3 years ago
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