Answer:
The following histogram shows the relative frequencies of the height recorded to the nearest inch of population of women the mean of the population is 64.97 inches and the standard deviation is 2.66 inches
(a) Based on the histogram, what is the probability that the selected woman will have a height of at least 67 inches? Show your work
Answer:
0.22268
Step-by-step explanation:
z-score is z = (x-μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation.
(a) Based on the histogram, what is the probability that the selected woman will have a height of at least 67 inches? Show your work
At least means equal to or greater than 67 inches
z = 67 - 64.97/2.66
z = 0.76316
P-value from Z-Table:
P(x<67) = 0.77732
P(x>67) = 1 - P(x<67) = 0.22268
The probability that the selected woman will have a height of at least 67 inches is 0.22268
Step-by-step explanation:
By unit rate they mean feet per second
To do this you need to divide feet by seconds
692.08/21.1=32.8
The unit rate is:
32.8 feet per second
-6 + x = -7
+6 +6 add 6 to both sides, 6's cancel out on the left.
________
x = -1, is the answer.
Hope this helps! Let me know if you have any other questions related to this problem. :)
Let x be Juilo's normal hourly rate.
so for the 35 hr week we have:-
30x + 5*1.4x = 436.60
37x = 436.60
x = 436.60 / 37 = $11.80
His normal hourly rate = $11.80
So for a 30 hr week he will earn 11.80 * 30 = $354
So the amount $436.60 is a reasonable figure for a 35 hr week.
