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Bas_tet [7]
3 years ago
9

Help me please I’ll give extra points

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0
THE NEW COODINATES
U( -4,-6)
Now( 6,-4)
S( -8,-10)
Now (10,-8)
T(-3,-10)
Now(10,-3)
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What is the solution set for the following inequality? 4x – 3 + 6x > 5x + 7
sp2606 [1]

Answer:

you got that

Step-by-step explanation:

wet wet wet

7 0
2 years ago
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F(x) = x2 + 1<br> What is f(f(x))?<br> O x + 2x²+1<br> O x + 2x²+2<br> x + 2<br> x+1
nadya68 [22]

Answer:

It's x^4+2x^2+2

Step-by-step explanation:

The argument of f(f(x)) function becomes x^2+1-> F=(x^2+1)^2+1 Opening the brackets you get my answer. Not sure if O sign stood for ^4.

5 0
4 years ago
Given the equation f(x) = 35(1.3)x. Which of the following situations could this equation represent?
kramer
Both b and c
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5 0
3 years ago
Please HELPPPP me !!!!!
dedylja [7]

Answer:

y = 4x - 3\\Slope \ m_1 = 4

EQUATION OF LINE PERPENDICULAR

Lines \ are \  perpendicular => m_1 \cdot m_2 = -1\\

slope, m_2 = \frac{-1}{4}

equation \ of \ the\ line \ passing \ through \ (-2, 2) \ slope ,m_2 :\\(y - y_2) =m_2(x - x_2)\\ (y - 2) = \frac{-1}{4} (x -(-2))\\\\y - 2 = \frac{-1}{4} (x +2)\\\\y = \frac{-1}{4}x - \frac{1}{2}  + 2\\\\y = \frac{-1}{4}x + \frac{3}{2}

EQUATION OF LINE PARALLEL

Lines \ are \ parallel => m_1 \cdot m_3 = 1\\slope, m_3 = \frac{1}{4}Equation \ of \ the \ line \ through \ (-2, 2) \ and \ slope, m_3:\\(y - y_3) =m_3(x - x_3)\\\\(y-2) = \frac{1}{4} (x - (-2))\\\\y-2 = \frac{1}{4}(x+2)\\\\y = \frac{1}{4}x + \frac{1}{2} +2\\\\y = \frac{1}{4}x + \frac{5}{2}

6 0
3 years ago
What is the additive inverse of the following:-5x?
Anvisha [2.4K]

Answer:

The additive inverse of 5 is -5.

Step-by-step explanation:

In mathematics, the additive inverse of a number a is the number that, when added to a, yields ... Other properties. 2 Formal definition; 3 Other examples; 4 Non-examples; 5 See also; 6 Notes and references ... Other properties[edit]. In addition to the identities listed above, negation has the following algebraic properties:.

7 0
3 years ago
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