Answer:
The minimum value of f(x) is -21 and it occurs at x = 1
Step-by-step explanation:
f(x) =3x^2-6x-18
Factor out the greatest common factor out of the first two terms
f(x) =3(x^2-2x)-18
Complete the square
-2x/2 =-1 (-1)^2 = 1
Add 1 (But remember the 3 out front so we are really adding 3 so we need to subtract 3 to remain balanced)
f(x) = 3(x^2 -2x+1) -3 -18
f(x) = 3(x-1)^2 -21
This is vertex form
f(x) = a(x-h)^2 +k where (h,k) is the vertex and a is a constant
The vertex is (1,-21)
Since a > 0 this opens upward and the vertex is a minimum
The minimum value of f(x) is -21 and it occurs at x = 1
Answer:
3rd option
Step-by-step explanation:
Using the identities
cot x = 
csc² x = 1 + cot² x
Given
tanθ = 
, then cotθ = 
csc²θ = 1 + ( )² = 1 + 
= 
cscθ = ± 
= ± 
Since θ is in 3rd quadrant, then cscθ < 0
cscθ = - × 
= - 
Answer:
are there any word choices?
Step-by-step explanation:
Doubling (2 times ) the quantity (indicates a group) of a number (x) decreaded by (-) 6 (6) is less than (<) negative 36 (-36
2 times (x-6)<-36
divide both sides by 2
x-6<-36
add 6 to both sides
x<-30
