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2 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

liubo4ka [24]2 years ago

4 0

Answer:

44.81%

Step-by-step explanation:

First determine the z-scores for 3.5 and 5.5 years. After matching the z-scores with the areas under the standard normal curve, subtract the smaller area from the larger area to solve.

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30GB trust me I will not let you fail

Step-by-step explanation:

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2 years ago

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At Gloria’s Restaurant, the average diner tips the waiter 20% of their total bill (cost of meal). Jacob's bill was $66 How much

-Dominant- [34]

Answer:

Jacob should pay $13.20 for the tip.

Step-by-step explanation:

The equation is: (66)(0.2) = 13.20

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2 years ago

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the perimeter of equilateral triangular Garden is 18 ft. The side lengths are 3x feet. what is the value of x?

Yuliya22 [10]

X = 2

18 / 3 = 2

2 * 6 = 6

6 + 6 + 6 = 18

Hope this helps.

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3 years ago

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Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

suppose the annual rate of inflation average 3.8% over the next 10 years. the present cost of oil change for tour car is $23.95.

Mariana [72]

If the annual rate in 10 years has the same quadralaterical value the answer would be 47.9 but we can make sure our answer is correct
what we know:

The cost changed in 10 years to 23.95

if the cost changed another 10 years it would be another 23.95, 23.95+23.95=47.9 Which is our answer pls mark brainliest

4 0

3 years ago