A is correct
The slides would have the specimen on it as well
c would be the correct answer to this question
q=0,78
To calculate the frequency of the allele we use the Hardy-Weinberg equation. The Hardy-Weinberg equation is used to calculate the genetic variation of a population at equilibrium. If the alleles are A and a, p is the frequency of the allele A and q is the frequency of the allele a. Hardy-Weinberg equation for alleles A and a:
p² + 2pq + q² = 1
p² is the frequency of the homozygous genotype AA, 2pq is the frequency of the heterozygous genotype Aa and q² is the frequency of the homozygous genotype aa.
p²+2pq+q²=(p+q)²=1
p+q=1
<span>If p=0,22 q=1-0,22=0,78</span>
