Given two points. we can find the equation of a line passing through the points
The formula to be used is:
![\frac{y_2-y_1}{x_2-x_!}=\frac{y-y_1}{x-x_!}](https://tex.z-dn.net/?f=%5Cfrac%7By_2-y_1%7D%7Bx_2-x_%21%7D%3D%5Cfrac%7By-y_1%7D%7Bx-x_%21%7D)
where
![x_1=3,y_!=-2,x_2=3,y_2=4](https://tex.z-dn.net/?f=x_1%3D3%2Cy_%21%3D-2%2Cx_2%3D3%2Cy_2%3D4)
![\frac{4-(-2)}{3-3}=\frac{y-(-2)}{x-3}](https://tex.z-dn.net/?f=%5Cfrac%7B4-%28-2%29%7D%7B3-3%7D%3D%5Cfrac%7By-%28-2%29%7D%7Bx-3%7D)
=>
![\frac{6}{0}=\frac{y+2}{x-3}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B0%7D%3D%5Cfrac%7By%2B2%7D%7Bx-3%7D)
The next step is to cross multiply
![6(x-3)=0(y+2)](https://tex.z-dn.net/?f=6%28x-3%29%3D0%28y%2B2%29)
=>
![6(x-3)=0](https://tex.z-dn.net/?f=6%28x-3%29%3D0)
Divide both sides by 6 and make x the subject
x=3
The answer is 33.3 repeating
Answer:
No.
If two rectangles are congruent, it means they are the exact same shape and size.
I have uploaded an image with this answer. In the image, you can see two rectangles with the same perimeter. However, they are not congruent because they are not of the same size (even though they are of the same shape - a rectangle).
Hence, two rectangles may not be congruent if they have the same perimeter.
Based on the fact that the road sign's distance to Beaston is rounded to the nearest unit, the actual range of possible miles to Beaston is 9.50 ≤ x ≤ 10.49.
<h3>How far is it to Beaston?</h3>
Based on the fact that the miles to Beaston are rounded to the nearest mile, the first thing to do is to find the lowest and highest numbers that can be rounded to 10 miles.
The lowest number that you can round to 10 miles is:
= 9.5 miles
Because of the 0.5 attached to the 9 miles, you will round up to 10 instead of down to 9.
The highest number that you can round to 10 miles at two decimal places is 10.49 miles.
The reason this is the highest is that the 0.4 is the tenths number just before 0.5. This means that you round the whole number down to 10.
Assuming the distance to Beaston is x, the interval would then be:
9.50 ≤ x ≤ 10.49.
In conclusion, the range of miles of Beaston is 9.50 ≤ x ≤ 10.49.
Find out more on interval notation at brainly.com/question/27910869
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Answer:
−2y3+4y2+18x+8
Step-by-step explanation:
Let's simplify step-by-step.
4(y2+2)+6x−2y3+12x
Distribute:
=(4)(y2)+(4)(2)+6x+−2y3+12x
=4y2+8+6x+−2y3+12x
Combine Like Terms:
=4y2+8+6x+−2y3+12x
=(−2y3)+(4y2)+(6x+12x)+(8)
=−2y3+4y2+18x+8