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ycow [4]
3 years ago
9

Which statement comparing ​ |−12| ​ and ​ |8| ​ is true? ​ |−12|>|8| ​ ​ |−12|=|8| ​ |−12|<|8|

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0

|-12|>|8|                                                  

have a great day

joja [24]3 years ago
4 0

In this question we have two absolute values which are

|-12| \  and \ |8|

Absolute value is always positive. That is absolute value of negative number is the positive number and absolute value of positive number is again a positive number.

So we have

|-12| =12 \\ | 8| = 8

And

12>8

So the correct option is the first option, that is ,

|-12| > |8|

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Write the equation of the line passing through (-3, 4) and normal to -2x + 7y = -3. (Note: normal means perpendicular)
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Answer:

The answer to your question is     y = -7/2x -13/2

Step-by-step explanation:

Point = (-3, 4)

Line   -2x + 7y = -3

Process

1.- Solve equation for y to find the slope of the perpendicular line

                  7y = 2x - 3

                    y = 2/7 x - 3/7

slope = 2/7

Slope of the perpendicular line = -7/2

2.- Find the equation of the new line

                   y - y1 = m(x - x1)

                   y - 4 = -7/2(x + 3)

                   y - 4 = -7/2x - 21/2

                   y = -7/2x - 21/2 + 4

                   y = -7/2x -21/2 + 8/2

3.- Result

                   y = -7/2x -13/2

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