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3 years ago

Find the perimeter of the triangle. A) 20 B) 51 C) 12 + 74 D) 12 + 47

Mathematics

2 answers:

masya89 [10]3 years ago

7 0

D i know i’ve done it

zysi [14]3 years ago

3 0

The answer of the question is D

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This year a small business had a total revenue of 48,300 if this is 38% more than their total revenue the previous year what was

riadik2000 [5.3K]

Answer:

$48,300

100 + 38% = 138% or 1.38

$48,300 / 1.38 = $35,000

Check:

$35,000 * 1.38 = $48,300

$35,000 * .38 = $13,300 (raise) + salary $35,000 = $48,300

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Whats the answer to this please

anastassius [24]

Y = 3x
so
if x = 5 then y = 15
if x = 10 then y = 30

so a = 10 and b = 15

answer is B. second choice
a = 10 and b = 15

3 0

3 years ago

The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 < T < 36 , where T is

antoniya [11.8K]

Answer:

$N(T(t)) = 1408t^2 - 385.6t - 105.52$

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

$N(T(t)) = 22 * (8t + 1.7)^2 - 123 * (8t + 1.7) + 40$

$N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40$

$N(T(t)) = 1408t^2 + 598.4t + 63.58 - 984t - 169.1$

$N(T(t)) = 1408t^2 - 385.6t - 105.52$

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

$8019 = 1408t^2 - 385.6t - 105.52$

$1408t^2 - 385.6t - 8124.52 = 0$

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0

3 years ago

BRAIN TO CORRECT ANSWER!!

zmey [24]

Answer:

It is B

Step-by-step explanation:

3 0

2 years ago

Why is 3 + (−5) equal to −2?

tamaranim1 [39]

Answer: since the 5 is a negative you are subtracting it from 3

so 3 +(-5) is actually 3-5. which = -2

Step-by-step explanation:

Hope this helps

5 0

3 years ago