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Virty [35]
3 years ago
5

If an object has zero velocity, will the object be in motion? Why or why not?

Chemistry
2 answers:
aksik [14]3 years ago
5 0

Answer:

The object will not  be in motion

Explanation:

An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. ... Objects resist changes in their velocity.

ale4655 [162]3 years ago
4 0

Answer:

Yes it can be in motion

Explanation:

Even though it stopped, i.e the velocity is zero, the acceleration would be the acceleration due to gravity, 9.8 m/s. Acceleration can only be calculated over a period of time. This means, even if the motion of the body changes after infinitesimally small period of time, the object will have an acceleration.

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At a certain temperature, the K p for the decomposition of H 2 S is 0.859 . H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g ) Initially, o
serious [3.7K]

Answer:

P = 0.444 atm

Explanation:

The reaction of decomposition of H₂S is:

                    H₂S(g)   ⇄  H₂(g)  + S(g)      

<em>Initial</em>            0.245          0           0

<em>Equilibrium  </em>0.245-x       x            x

The equilibrium constant (Kp) of the above reaction is the following:

K_{p} = \frac{P_{H_{2}}*P_{S}}{P_{H_{2}S}}     (1)

Knowing that initally, only H₂S is present at P = 0.245, the Kp of equation (1) at equilibrium is:

0.859 = \frac{x*x}{0.245 - x}  

x^{2} -0.859*0.245 + 0.859x = 0

Using the quadratic formula we get x₁ = 0.199 and x₂ = -1.058.

Taking only the possitive number we have that:

P_{H_{2}} = P_{S} = x = 0.199 atm      

P_{H_{2}S} = (0.245 - 0.199) atm = 0.046 atm      

Therefore, the total pressure in the container at equilibrium is:

P_{T} = P_{H_{2}} + P_{S} + P_{H_{2}S} = (0.199*2 + 0.046) atm = 0.444 atm

I hope it helps you!

4 0
3 years ago
The free energy obtained from the oxidation (reaction with oxygen) of glucose (C6H12O6) to form carbon dioxide and water can be
babunello [35]

Answer:

The correct answer is -2878 kJ/mol.

Explanation:

The reaction that takes place at the time of the oxidation of glucose is,  

C₆H₁₂O₆ (s) + 6O₂ (g) ⇒ 6CO₂ (g) + 6H₂O (l)

The standard free energy change for the oxidation of glucose can be determined by using the formula,  

ΔG°rxn = ∑nΔG°f (products) - ∑nΔG°f (reactants)

The ΔG°f for glucose is -910.56 kJ/mol, for oxygen is 0 kJ/mol, for H2O -237.14 kJ/mol and for CO2 is -394.39 kJ/mol.  

Therefore, ΔG°rxn = 6 (-237.14) + 6 (-394.39) - (-910.56)

ΔG°rxn = -2878 kJ/mol

8 0
3 years ago
A sample of gas has a volume of 526 mL at 346 mmHg and 35.0°C. Determine the moles of gas.​
Furkat [3]

Answer:

The moles of gas is 0.009474 moles.

Explanation:

Given that,

Volume = 526 mL

Pressure = 346 mmHg

Temperature = 35.0°C

We need to calculate the moles of gas

Using formula of ideal gas

n=\dfrac{PV}{RT}

Where, P = pressure

V = volume

R = gas constant

T = temperature

Put the value into the formula

n=\dfrac{\dfrac{346}{760}\times0.526}{0.08206\times(35+273)}

n=0.009474\ moles

Hence, The moles of gas is 0.009474 moles.

7 0
3 years ago
You and a friend move a grand piano across the living room, exerting 25 newtons of force and performing 175 joules of work. It t
agasfer [191]
<h3>Answer:</h3>

Distance = 7 m

Power = 12.5 J/s or watts

<h3>Explanation:</h3>

Work done = 175 Joules

Force exerted = 25 Newtons

Work done is the product of force exerted and the distance moved by a body.

Therefore;

Work done = Force × distance

Rearranging the formula we can work out the distance;

Distance = work done ÷ Force

              = 175 J ÷ 25 N

             =  7 m

Thus, the grand piano was moved by 7 m across the living room .

On the other hand,

Power is the rate at which the work is done.

Therefore;

Power = Work done ÷ time

Work done = 175 Joules

Time = 14 seconds

Thus;

Power generated = 175 J ÷ 14 sec

                            = 12.5 J/s or watts

Hence, a power of 12.5 J/s was generated in moving the grand piano.

8 0
4 years ago
A paper burning is A.heat or B.chemical
Marina CMI [18]
It should probably be chemical
7 0
3 years ago
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