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3 years ago

explain how chemists can state with certainty that no one will discover an element between sulfur and chlorine?

1 answer:

4 0

<span>Elements are distinguished based on their number of protons. Chlorine has exactly one proton more than sulfur. Since there cannot be fractions of protons, there can be no element between sulfur and chlorine on the periodic table.</span>

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Which statement describes how the binary ionic compound cacl2 is named?

Oksi-84 [34.3K]

Calcium Chloride because it is a type 1 so the the anion ends with -ide

6 0

2 years ago

To what category of elements does an element belong if it's a poor conductor of electricity

Karo-lina-s [1.5K]

Answer:

I would assume NON-METALS

7 0

4 years ago

HELPP ME PLEASE!! What would be the density of a 40 g object that displaces 10 ml of water?

Snezhnost [94]

Answer:

<h2>The answer is 4.0 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 40 g

volume = 10 mL

The density of the object is

$density = \frac{40}{10} = 4 \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are

olga nikolaevna [1]

<u>Answer:</u> The standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

<u>Explanation:</u>

We are given:

$K_{sp}\text{ of }Ag_2S=8\times 10^{-51}$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[273+25]K=298K$

K = equilibrium constant or solubility product = $8\times 10^{-51}$

Putting values in above equation, we get:

$\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ$

For the given chemical equation:

$Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)$

The equation used to calculate Gibbs free change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]$

The equation for the Gibbs free energy change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]$

We are given:

$\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ$

Putting values in above equation, we get:

$285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol$

Hence, the standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

8 0

3 years ago

Is xenon (xe) more or less reactive than bromine (br)? why?

galben [10]

Answer:

Xenon is less reactive.

Explanation:

Xenon is a noble gas with 8 valence electrons whereas bromine is a halogen with 7 and is very reactive.

7 0

3 years ago