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tangare [24]
3 years ago
10

Convert: 65 kg to mg 65,000 mg O 65,000,000 mg O 65 mg

Chemistry
2 answers:
Eduardwww [97]3 years ago
5 0
65,000,000mg
Reasoning: move the decimal point 6 places to the right (right because it’s going to a smaller unit)
makkiz [27]3 years ago
3 0

Answer:

kg, mg. 65.00, 65,000,000. 65.01, 65,010,000. 65.02, 65,020,000. 65.03, 65,030,000. 65.04, 65,040,000. 65.05, 65,050,000. 65.06, 65,060,000.

Explanation:

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omeli [17]

Answer:

Fossils tell us when organisms lived, as well as provide evidence for the Fossils are the preserved remains or traces of animals, plants, and other organisms from the past. Fossils, by comparing the anatomies of both modern and extinct species, allows scientists to study the skin, hair, and organs of ancient creatures.

Explanation:

6 0
3 years ago
What is the concentration of the hydroxide ion given that the concentration of the hydronium ion?
Sergio039 [100]

The concentration of the hydroxide ion given that the concentration of the hydronium ion 1.0 times 10^-14 M. The reverse mathematical method used to determine the pOH can be used to get the hydroxide ion concentration from the pOH. How many hydroxide ions are there in a solution with a pOH of 5.70, for instance.

Calculate 10-5.70, or "inverse" log, on a calculator (- 5.70). It indicates that one hydroxide ion is produced by one part of the NaOH solution. Because of this, the molar concentration of hydroxide ions in the solution is the same as the molar concentration of the NaOH.

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6 0
1 year ago
Which statement best explains why a carbon atom can bond easily with other atoms?
Kruka [31]
The best and most correct answer among the choices provided by the question is the second choice.

Carbon can easily bond with other atoms because it is an organic element.

I hope my answer has come to your help. God bless and have a nice day ahead!
3 0
3 years ago
Read 2 more answers
) How many moles are there in 2.00 x 10^19 molecules of calcium phosphate?
Tamiku [17]

Answer:

\huge 3.322 \times  {10}^{ - 5}  \:  \: moles  \\

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{2.00 \times  {10}^{19} }{6.02 \times  {10}^{23} }  \\  \\  = 3.322 \times  {10}^{ - 5}  \:  \: moles

Hope this helps you

4 0
3 years ago
A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-
Komok [63]

<u>Answer:</u> The cell potential of the cell is +0.118 V

<u>Explanation:</u>

The half reactions for the cell is:

<u>Oxidation half reaction (anode):</u>  Ni(s)\rightarrow Ni^{2+}+2e^-

<u>Reduction half reaction (cathode):</u>  Ni^{2+}+2e^-\rightarrow Ni(s)

In this case, the cathode and anode both are same. So, E^o_{cell} will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

[Ni^{2+}_{diluted}] = 1.00\times 10^{-4}M

[Ni^{2+}_{concentrated}] = 1.0 M

Putting values in above equation, we get:

E_{cell}=0-\frac{0.0592}{2}\log \frac{1.00\times 10^{-4}M}{1.0M}

E_{cell}=0.118V

Hence, the cell potential of the cell is +0.118 V

5 0
3 years ago
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