Answer:
Answer: The mean increases by 3
Step-by-step explanation:
The original data set is
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}
The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.
The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77
If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80
So in summary so far
old mean = M = 77
new mean = N = 80
The difference in values is N-M = 80-77 = 3
So that's why the mean increases by 3
Answer:
V=343in³
Step-by-step explanation:
A=6a2
V=a
3V=6A3/2
36=6·2943/2
36=343in³
Suppose the line is y=mx+b
when x=3, y=15, so 15=3m+b
when x=-1, y=-13, so -13=-m+b
solve the system of these two equation, you get m=7, b=-6
so the linear equation is y=7x-6
Answer:
361.7cm²
Step-by-step explanation:
Volume of sphere 1= 8cm³
=
Volume of sphere 2 = 647cm³
But volume of sphere = 4/3πr³
The radius of sphere 2
647 = 4/3πr³
((3*647)/4)/π= r³
5.36544 = r
Surface area = 4πr²
Surface area for the big sphere
= 4π5.36544²
= 361.7cm²
Answer:
TRUE
Step-by-step explanation:
Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.
We know that corresponding angles formed by transversal line are congruent.
Hence ∠JKL = ∠ MLK ...(i)
Now consider triangles JKL and MLK
JK = LM {Given}
∠JKL = ∠ MLK { Using (i) }
KL = KL {common sides}
Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congurent.
Hence given statement is TRUE.
