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Artyom0805 [142]
3 years ago
7

Help I tried to do the page but I couldn't

Mathematics
1 answer:
ahrayia [7]3 years ago
6 0
Sarah wanted to share her apple with 3 of her friends , but she only had 1/2 of an apple left. What math problem should she write to figure out how to split her apple. Explain your answer.
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Need answer ASAP!!!!!
MissTica

Answer:

30/42 = 10/14 = 5/7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A ticke cost 40 dollars suppose every seat in the first ten rolls are filled what is the total revenue from those seatss
KonstantinChe [14]
If a single ticket costs 40 dollars then the ten seats will generate the following

$40 x 10= $400

7 0
3 years ago
The meal cost$ 54.65 and they want to leave they waiter a 20% how much should the tip be
SSSSS [86.1K]

Answer:

10.93

Step-by-step explanation

54.65 x 0.20 = 10.93

4 0
3 years ago
B 95 C a e 75° 709 ITEM BANK: Move to Bottom 25° 30° 35° 50° 75° 85°​
den301095 [7]

Answer:

85 California spout alone 1

3 0
3 years ago
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
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